Answer:
Given:
Sample size, n = 120
P = 48% = 0.48
p' = = 0.4
Significance level = 0.10
Null and alternative hypotheses are:
H0 : P = 0.48
H1 : P ≠ 0.48
For the test statistics:
Z = -1.754
P-value: This is a two tailed test.
For Z = -1.754 the P-value = 0.7943
Critical value: a = 0.10, 2 tailed test, Z critical = +1.645, -1.645
Decision Rule: We reject H0, if pvalue is less than significance level. We also reject H0 is Z observed is greater than Z critical.
Decision: Since pvalue, 0.7943 is greater than significance level, 0.10 we fail to reject null hypothesis, H0.
Conclusion:
There is not enough sufficient evidence to conclude that percentage of people who believe there is life on other planets differs from 48%
She needs to score at least 16 points in the second game to receive a trophy.
<h3>
Answer: approximately 2.11</h3>
Work Shown:
x = 108 is the raw score we want to transform
mu = 104 is the mean
sigma = 1.9 is the standard deviation
z = (x-mu)/sigma
z = (108-104)/1.9
z = 4/1.9
z = 2.10526315789473 which is approximate
z = 2.11 rounding to two decimal places
I'm rounding to two decimal places because many z tables will work with this level of precision.
You will make 11588 mor dollars for the hourly job