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ElenaW [278]
3 years ago
11

How does the height from which you drop the ball relate to the height that the ball bounces back up?

Physics
1 answer:
Stels [109]3 years ago
7 0
The higher you go the more potential energy there is, and the lower it is the more kinetic energy there is, so the more kinetic energy there is the higher the ball will bounce.
You might be interested in
Hey! anybody knows the answer then help me i will mark your answer!!!
Volgvan

10/9

Explanation:

option 2 is the correct answer

8 0
3 years ago
Calculate the de Broglie wavelength of an electron accelerated from rest through a potential difference of (a) 100 V, (b) 1.0 kV
forsale [732]

Answer:

(a) \lambda=1.227\ A

(b) \lambda=0.388\ A

(c) \lambda=0.038\ A

Explanation:

Given that,

(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :

\lambda=\dfrac{h}{\sqrt{2meV} }

Where

m and e are the mass of and charge on an electron

On solving,

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

V = 100 V

\lambda=\dfrac{12.27}{\sqrt{100} }\ A

\lambda=1.227\ A

(b) V = 1 kV = 1000 V

\lambda=\dfrac{12.27}{\sqrt{V} }\ A

\lambda=\dfrac{12.27}{\sqrt{1000} }\ A

\lambda=0.388\ A

(c) If V=100\ kV=10^5\ V

\lambda=\dfrac{12.27}{\sqrt{10^5} }\ A

\lambda=0.038\ A

Hence, this is the required solution.

7 0
3 years ago
A bullet with a mass of 0.3 kg is fired out of a gun with a mass of 4 kg at 600 m/s. What is the recoil velocity on the gun?
slavikrds [6]

Answer:

According to the Conservation of Momentum,

Momentum of the gun = momentum of the bullet

M(gun)×V(gun)=m(bullet)×v(bullet)

4kg × V = 0.3kg × 600m/s²

V = (0.3 × 600)/4 = 45 m/s

The recoil velocity on the gun is <em><u>45 m/s</u></em>

<h3><u>45 m/s</u> is the right answer.</h3>
4 0
3 years ago
The wave speed on a string under tension is 200 m/s. What is the speed if the tension is doubled?
Maksim231197 [3]

Answer:

v = 282.84 m / s

Explanation:

The speed of a wave in a wire is given by the equation

       .v = √ T /ρ

Where v is the speed of the wave, T the tension in the wire and ρ the density of the wire

 If the tension is doubled

        T = 2T₀

        v = √ (2T₀ / ρ)

        v = √2   √ T₀ / ρ

        v = √2  v₀

calculate

       v = √2  200

       v = 282.84 m / s

3 0
3 years ago
Show work/ no links
ryzh [129]
7) p=w/t
2620/0.2
=13100W

8) W=pt
40*30
=1200 J

9) transformed
7 0
3 years ago
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