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3 years ago

How does the height from which you drop the ball relate to the height that the ball bounces back up?

1 answer:

7 0

The higher you go the more potential energy there is, and the lower it is the more kinetic energy there is, so the more kinetic energy there is the higher the ball will bounce.

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Consider two copper wires. one has twice the length and twice the cross-sectional area of the other. how do the resistances of t

Anestetic [448]

Answer:

R = ρ L / A where R is the resistance and ρ the resistivity:

R2 / R1 = (L2 / A2) / (L1 / A1) = L2 * A1 / (L1 * A2)

R2 / R1 = (2 L * A) / (L * 2 A) = 1

Their resistances should be the same.

5 0

2 years ago

A tennis ball hits with an initial velocity of 25 m/s [10 o above the

Sav [38]

First, calculate the components of its initial velocity v0:

v0x = v0cos10 = 24.6 m/s

v0y = v0sin10 = 4.34 m/s

The ball reaches its peak when vy = 0. Let's calculate the time it takes for vy to become zero:

vy = v0y - gt ---> t = v0y/g = 0.44 s

The horizontal distance it travels in this time is

x = v0xt = (24.6 m/s)(0.44 s)

= 10.8 m

Note that the net is 15 m away. After traveling a horizontal distance of 10.8 m, the height of the ball is

y = -(1/2)gt^2 + v0yt + 2.1

= -(4.9 m/s^2)(0.44 s)^2 + (4.34 m/s)(0.44 s) + 2.1 m

= -0.95 m + 1.9 m + 2.1 m

= 3.05 m

Note that this is the height of the ball at its peak. While the ball is well above the net at its peak, it is well short of its required horizontal distance to clear it. Instead, let's find the time it takes for the tennis ball to travel a horizontal distance of 15 m first:

x = v0xt ----> t = x/v0x = (15 m)/(24.6 m/s) = 0.61 s

Then calculate the height y when t = 0.61 s. If y > 0.9 m (height of the net), then the ball will clear the net.

y = -4.9t^2 + v0yt + 2.1

= -4.9(0.61 s)^2 + (4.34 m/s)(0.61 s) + 2.1 m

= -1.82 m + 2.65 m + 2.1 m

= 2.93 m

Yes, the ball will clear the net by 2.03 m.

3 0

3 years ago

you are riding on a train traveling 80 km/h. if you walk toward the back of the train at a speed of 1.2 km/h relative to the tra

Mazyrski [523]

Answer:

Velocity of the passenger = 78.8[km/h]

Explanation:

In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.

In such a way that the passenger moves in a direction contrary to the movement of the train.

$v_{pass}=80-1.2\\ v_{pass}=78.8[km/h]$

The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.

6 0

3 years ago

Important result of french revolution

qaws [65]

The french revolution led to many deaths and impacted history because of the amount of life lost

8 0

3 years ago

NET FORCE ( PLEASE ANSWER ASAP )

slava [35]

First picture (black background): 50 Newtons UP

Second picture (white background): 30 Newtons RIGHT

3 0

4 years ago