<span>Density is a measure of an object's </span>mass per unit of volume
Which means that it shows how much mass is contained within a volume of something.
Accuracy is a general concept while precision is more of a mathematical concept.
Light that enters the new medium <em>perpendicular to the surface</em> keeps sailing straight through the new medium unrefracted (in the same direction).
Perpendicular to the surface is the "normal" to the surface. So the angle of incidence (angle between the laser and the normal) is zero, and the law of refraction (just like the law of reflection) predicts an angle of zero between the normal and the refracted (or the reflected) beam.
Moral of the story: If you want your laser to keep going in the same direction after it enters the water, or to bounce back in the same direction it came from when it hits the mirror, then shoot it <em>straight on</em> to the surface, perpendicular to it.
Answer:x=2 and x=3
Explanation:
Given
Potential Energy for a certain mass is
![U(x)=2x^3-15x^2+36x-23](https://tex.z-dn.net/?f=U%28x%29%3D2x%5E3-15x%5E2%2B36x-23)
and we know force is given by
![F=-\frac{\mathrm{d} U}{\mathrm{d} x}](https://tex.z-dn.net/?f=F%3D-%5Cfrac%7B%5Cmathrm%7Bd%7D%20U%7D%7B%5Cmathrm%7Bd%7D%20x%7D)
![F=-(2\times 3x^2-15\times 2x+36)](https://tex.z-dn.net/?f=F%3D-%282%5Ctimes%203x%5E2-15%5Ctimes%202x%2B36%29)
For Force to be zero F=0
![\Rightarrow 6x^2-30x+36=0](https://tex.z-dn.net/?f=%5CRightarrow%206x%5E2-30x%2B36%3D0)
![\Rightarrow x^2-5x+6=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2-5x%2B6%3D0)
![\Rightarrow x^2-2x-3x+6=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%5E2-2x-3x%2B6%3D0)
![\Rightarrow (x-2)(x-3)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-2%29%28x-3%29%3D0)
Therefore at x=2 and x=3 Force on particle is zero.
(a) The momentum of the proton is determined as 5.17 x 10⁻¹⁸ kgm/s.
(b) The speed of the proton is determined as 3.1 x 10⁹ m/s.
<h3>
Momentum of the proton</h3>
The momentum of the proton is calculated as follows;
K.E = ¹/₂mv²
where;
- m is mass of proton = 1.67 x 10⁻²⁷ kg
- v is speed of the proton = ?
<h3>Speed of the proton</h3>
v² = 2K.E/m
v² = (2 x 50 x 10⁹ x 1.602 x 10⁻¹⁹ J)/(1.67 x 10⁻²⁷)
v² = 9.6 x 10¹⁸
v = 3.1 x 10⁹ m/s
<h3>Momentum of the proton</h3>
P = mv = (1.67 x10⁻²⁷ x 3.1 x 10⁹) = 5.17 x 10⁻¹⁸ kgm/s
Learn more about momentum here: brainly.com/question/7538238
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