Answer:
that's true.
Explanation:
that's the reason why oxygen supports burning.
Answer:
The image height is 3.0 cm
Explanation:
Given;
object distance,
= 15.0 cm
image distance,
= 5.0 cm
height of the object,
= 9.0 cm
height of the image,
= ?
Apply lens equation;
![\frac{h_i}{h_o} = -\frac{d_i}{d_o}\\\\ h_i = h_o(-\frac{d_i}{d_o})\\\\h_i = -9(\frac{5}{15} )\\\\h_i = -3 \ cm](https://tex.z-dn.net/?f=%5Cfrac%7Bh_i%7D%7Bh_o%7D%20%3D%20-%5Cfrac%7Bd_i%7D%7Bd_o%7D%5C%5C%5C%5C%20h_i%20%3D%20h_o%28-%5Cfrac%7Bd_i%7D%7Bd_o%7D%29%5C%5C%5C%5Ch_i%20%3D%20-9%28%5Cfrac%7B5%7D%7B15%7D%20%29%5C%5C%5C%5Ch_i%20%3D%20-3%20%5C%20cm)
Therefore, the image height is 3.0 cm. The negative values for image height indicate that the image is an inverted image.
Answer:
just before landing the ground
Explanation:
Let the velocity of projection is u and the angle of projection is 30°.
Let T is the time of flight and R is the horizontal distance traveled. As there is no force acting in horizontal direction, so the horizontal velocity remains constant. Let the particle hits the ground with velocity v.
initial horizontal component of velocity, ux = u Cos 30
initial vertical component of velocity, uy = u Sin 30
Time of flight is given by
![T = \frac{2u Sin\theta }{g}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2u%20Sin%5Ctheta%20%7D%7Bg%7D)
Final horizontal component of velocity, vx = ux = u Cos 30
Let vy is teh final vertical component of velocity.
Use first equation of motion
vy = uy - gT
![v_{y}=u_{y}- g \times \frac{2u Sin\theta }{g}](https://tex.z-dn.net/?f=v_%7By%7D%3Du_%7By%7D-%20g%20%5Ctimes%20%5Cfrac%7B2u%20Sin%5Ctheta%20%7D%7Bg%7D)
![v_{y}=u Sin 30 - 2u Sin 30](https://tex.z-dn.net/?f=v_%7By%7D%3Du%20Sin%2030%20-%202u%20Sin%2030)
vy = - u Sin 30
The magnitude of final velocity is given by
![v = \sqrt{v_{x}^{2}+v_{y}^{2}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7Bv_%7Bx%7D%5E%7B2%7D%2Bv_%7By%7D%5E%7B2%7D%7D)
![v = \sqrt{\left (uCos 30 \right )^{2}+\left (uSin 30 \right )^{2}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cleft%20%28uCos%2030%20%20%5Cright%20%29%5E%7B2%7D%2B%5Cleft%20%28uSin%2030%20%20%5Cright%20%29%5E%7B2%7D%7D)
v = u
Thus, the velocity is same as it just reaches the ground.
The systems are geosphere ,hydrosphere, the atmosphere and the biosphere.