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3 years ago

An electrical circuit is a portable device that converts chemical energy into electrical energy

Physics

1 answer:

DerKrebs [107]3 years ago

7 0

Answer:

false a curciut is just a loop of electricity goes in and negative comes out when using a battery the negative goes in and the goes out making a battery have two sides to a uircute.

hope this helps!

Explanation:

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A metal rod A and a metal sphere B, on insulating stands, touch each other. They are originally neutral. A positively charged ro

ryzh [129]

Answer:

The sphere is positively charged

Explanation:

This is because when the positively charged rod is brought near the metal rod A, the electrons in metal rod A and sphere B are attracted towards it into metal rod A while the positive charges in the are repelled into sphere B. So, when the charged rod is withdrawn, and metal rod A and sphere B are separated, metal rod A is now negatively charged, but sphere B is positively charged.

So, sphere B is positively charged.

3 0

4 years ago

A load of bricks is lifted to the second floor of a building. How do work and power relate to this job?

Nady [450]

The faster the job is done, the greater the power

5 0

3 years ago

Read 2 more answers

Vf=V0+at solve for a

dangina [55]

Answer:

See below

Explanation:

vf = vo + at subtract vo from both sides

vf - vo = at now divide both sides by t

(vf-vo) / t = a

6 0

1 year ago

If a 25kg mass is dropped from a height of 5 meters what’s the work done by gravity

Elanso [62]

Answer:

Explanation:

M = 25kg

h = 5m

g = 9.8m/s2

Work done = mgh

Work done = 25 x 9.8 x 5

Work done = 1225J

8 0

3 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

KIM [24]

Answer:

a)Car E = Car D > (Car F = Car B = Car C) > Car A

b)Car E = Car D > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

$P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s$

<em>Car B:</em>

$P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s$

Car C:

$P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s$

Car D:

$P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s$

Car E:

$P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s$

Car F:

$P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s$

So the momentum is given as ,

Car E = Car D > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D > (Car F = Car B = Car C) > Car A

3 0

3 years ago