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BlackZzzverrR [31]
3 years ago
6

What is the line running through earth from pole to pole

Physics
2 answers:
Juliette [100K]3 years ago
8 0
Imaginary lines that run north and south map from pole to pole. meridians express degrees of longitued
Brut [27]3 years ago
6 0
The Longitutes are <em>imagenary lines that run from the North pole to the South pole.</em>
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Describe the difference between a scientific law and a scientific theory
Luda [366]
A scientific law is absolute, it cannot be proven wrong. A scientific theory is like a belief, it has been proven but can also be argued or disproven.
3 0
4 years ago
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A 2.7-kg block slides with a speed of 1.1 m/s on a frictionless, horizontal surface until it encounters a spring.
IceJOKER [234]

Answer

given,

mass of block = 2.7 kg

speed of block = 1.1 m/s

a) spring compressed to distance of 6 cm or 0.06 m

  using conservation of energy

kinetic energy is converted into spring energy

\dfrac{1}{2}mv^2= \dfrac{1}{2}kx^2

k =\dfrac{ mv^2}{x^2}

k =\dfrac{2.7\times 1.1^2}{0.06^2}

k= 907.5 N/m

b) again using conservation of energy

kinetic energy is converted into spring energy

\dfrac{1}{2}mv^2= \dfrac{1}{2}kx^2

v =\sqrt{\dfrac{kx^2}{m}}

v=\sqrt{\dfrac{907.5\times 0.015^2}{2.7}}

v=\sqrt{0.075625}

v= 0.275 m/s

8 0
3 years ago
Odyssey Quiz
Novosadov [1.4K]

Answer:

OD) 3.7 kg-m/s

Explanation:

given:

velocity of baseball, v = 25 m/s

angle below horizontal, Θ = 8^{o}

mass of baseball, m = 0.15 kg

Generally, momentum (p) is given by equation:

p = mv

Horizontal component is given by

p = mv cosΘ

  = 0.15 kg x 25 m/s x cos 8^{o}

  = 3.71 kg- m/s

Hence horizontal component of momentum is OD) 3.7 kg-m/s

4 0
4 years ago
A particle whose mass m=2 kg moves in the xy plane with a constant speed v= 3 m/s in the x direction along the line y = 5. What
Marianna [84]

Answer:

L= 30  kg.m²/s

Explanation:

Given that

m = 2 kg

v= 3 m/s along x direction

y= 5 m

As we know that

Linear momentum P

P = m v

The angular momentum is the moment of linear momentum.

So the angular momentum L

L = m v r

Here r= 5 m

By putting the values

L = m v r

L = 2 x 3 x 5  kg.m²/s

L= 30  kg.m²/s

5 0
3 years ago
A communications satellite orbiting the earth has solar panels that completely absorb all sunlight incident upon them. The total
Naddik [55]

Answer:

<em>1) 14 kW</em>

<em>2) 4.67 x 10^-5 N</em>

Explanation:

Area of solar panel = 10 m^2

Intensity of sun's radiation incident on earth = 1.4 kW/m^2

Solar power absorbed = ?

We know that the intensity of radiation on a given area is

I = \frac{P}{A}

where I is the intensity of the radiation

P is the power absorbed due to this intensity on a given area

A is the area on which this radiation is incident

From the equation, we have

P = IA

P = 1.4 kW/m^2  x  10 m^2 = <em>14 kW</em>

b) For a perfect absorbing surface, the radiation pressure is given as

p = I/c

where p is the radiation pressure

I is the incident light intensity = 1.4 kW/m^2 = 1.4 x 10^3 kW/m^2

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

p = (1.4 x 10^3)/(3 x 10^8) = 4.67 x 10^-6 Pa

we know that Force = pressure x area

therefore force on the solar panels is

F = 4.67 x 10^-6 x 10 = <em>4.67 x 10^-5 N</em>

6 0
3 years ago
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