The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three. Option B is correct.
<h3 /><h3>How do you calculate the volume of a cube?</h3>
Assume the side length of the cube under consideration is L units. The volume of the cube is then equal to L³ cubic units.
The volume of a cube is;
V = L³
Ubes have equal-length sides. The quickest technique to calculate the volume of a cube-shaped table is to use a ruler to measure one side, then multiply that figure by three.
Hence option B is correct.
To learn more about the volume of a cube refer
brainly.com/question/26136041
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Answer:
Deltoid Force, ![F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}](https://tex.z-dn.net/?f=F_%7Bd%7D%20%3D%20%5Cfrac%20%7Br_%7Ba%7Dmgsin%5Calpha_%7Ba%7D%7D%7Br_%7Bd%7Dsin%5Calpha_%7Bd%7D%7D)
Additional Information:
Some numerical information are missing from the question. However, I will derive the formula to calculate the force of the deltoid muscle. All you need to do is insert the necessary information and calculate.
Explanation:
The deltoid muscle is the one keeping the hand arm in position. We have two torques that apply to the rotating of the arm.
1. The torque about the point in the shoulder for the deltoid muscle,
2. The torque of the arm,
Assuming the arm is just being stretched and there is no rotation going on,
= 0
= 0
⇒ ![T_{Deltoid} = T_{arm}](https://tex.z-dn.net/?f=T_%7BDeltoid%7D%20%3D%20T_%7Barm%7D)
![r_{d}F_{d}sin\alpha_{d} = r_{a}F_{a}sin\alpha_{a}](https://tex.z-dn.net/?f=r_%7Bd%7DF_%7Bd%7Dsin%5Calpha_%7Bd%7D%20%3D%20r_%7Ba%7DF_%7Ba%7Dsin%5Calpha_%7Ba%7D)
Where,
is radius of the deltoid
is the force of the deltiod
is the angle of the deltiod
is the radius of the arm
is the force of the arm ,
which is the mass of the arm and acceleration due to gravity
is the angle of the arm
The force of the deltoid muscle is,
![F_{d} = \frac {r_{a}F_{a}sin\alpha_{a}}{r_{d}sin\alpha_{d}}](https://tex.z-dn.net/?f=F_%7Bd%7D%20%3D%20%5Cfrac%20%7Br_%7Ba%7DF_%7Ba%7Dsin%5Calpha_%7Ba%7D%7D%7Br_%7Bd%7Dsin%5Calpha_%7Bd%7D%7D)
but
,
∴ ![F_{d} = \frac {r_{a}mgsin\alpha_{a}}{r_{d}sin\alpha_{d}}](https://tex.z-dn.net/?f=F_%7Bd%7D%20%3D%20%5Cfrac%20%7Br_%7Ba%7Dmgsin%5Calpha_%7Ba%7D%7D%7Br_%7Bd%7Dsin%5Calpha_%7Bd%7D%7D)
No, there are not any carbon atoms inside this compound.
The compound is
. This means there are 3 "Ca" atoms and 2 "N" atoms.
- Ca is calcium
- N is nitrogen
Thus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
lipids are insoluble in water which is why lipids are often found in biological membranes and other waterproof coverings.