Two balls of equal mass at the bottom of an incline are rolled upward without slipping at the same initial velocity. one ball is
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Answer:
Speed of both blocks after collision is 2 m/s
Explanation:
It is given that,
Mass of both blocks, m₁ = m₂ = 1 kg
Velocity of first block, u₁ = 3 m/s
Velocity of other block, u₂ = 1 m/s
Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :
v = 2 m/s
Hence, their speed after collision is 2 m/s.
Answer:
Explanation:
The total force on the particle is given by
Then, by replacing we have:
where the cross product can be made with the determinant method.
Hope this helps!!