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Sav [38]
3 years ago
10

Two balls of equal mass at the bottom of an incline are rolled upward without slipping at the same initial velocity. one ball is

solid and the other is a thin-walled hollow ball. which rolls higher up the incline before coming to a stop?
Physics
1 answer:
Andrei [34K]3 years ago
6 0
The appropriate response would be the hollow ball.The purpose for it has more kinetic energy at the last (2/3 as opposed to 2/5) so it will have more potential energy (more height) at the best. Pondering it, more inertia implies its less impervious to change meaning the hollow ball with more inertia wont need to stop as fast.
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Sam is walking at 2m/s down the hallway when he realized he will be late to class. He speeds up to 4m/s and makes it to English
Salsk061 [2.6K]

Answer:

.5 m/s²

Explanation:

a= (vf-vi)/t

a= (4-2)/4

a=2/4

a= .5 m/s²

8 0
3 years ago
Find 4-5 animals and classify them into Prey, Predator, Carnivore, Omnivore, Herbivore.​
Sveta_85 [38]

Answer:

Koala, leopard, lion, cat, dog. Koala is an herbivore, leopard is a predator, lion is a predator, cat is a obligate carnivore, dogs are omnivores.

Explanation:

7 0
2 years ago
A record player turntable initially rotating at 3313 rev/min is braked to a stop at a constant rotational acceleration. The turn
Lelechka [254]

Answer:

a. 16 s b. -1.866 kJ

Explanation:

a. Since the initial rotational speed ω₀= 3313 rev/min = 3313/60 × 2π rad/s = 346.94 rad/s. Its rotational speed becomes ω₁ = 0.75ω₀ in time t = 4 s.

We find it rotational acceleration using α = (ω₁ - ω₀)/t = (0.75ω₀ - ω₀)/t = ω₀(0.75 - 1)/t = -0.25ω₀/t = (-0.25 × 346.94 rad/s)/4 s = -21.68 rad/s².

Since the turntable stops at ω = 0, the time it takes to stop is gotten from

ω = ω₀ + αt and t = (ω - ω₀)/α = (0 - 346.94 rad/s)/-21.68 rad/s² = (-346.94/-21.68) s = 16 s.

So it takes the turntable 16 s to stop.

b. The workdone by the turntable to stop W equals its rotational kinetic energy change.

So, W = 1/2Iω² - 1/2Iω₀² = 1/2 × 0.031 kgm² × 0² - 1/2 × 0.031 kgm² × (346.94 rad/s)² = 0 - 1865.7 J = -1865.7 J = -1.8657 kJ ≅ -1.866 kJ

3 0
3 years ago
Name two objects that both use electric motors and are commonly found in houses
Natali [406]
There's the fan over the stove and in the microwave oven, the dispose-all under the sink, the blender, the washer, the dryer, vacuum cleaner, hair dryer, and there are many in a computer.

Hope this helps!
3 0
3 years ago
Read 2 more answers
A 5.92 g object moving to the right at 17.1 cm/s makes an elastic head-on collision with an 11.84 g object that is initially at
Lelechka [254]

Answer:

v₁f = -5.7 cm/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

        m_{1} * v_{10} = m_{1} *v_{1f} + m_{2} * v_{2f} (1)

  • Rearranging terms, we have:

        m_{1} * (v_{10} - *v_{1f} ) = m_{2} * v_{2f} (2)

  • We also know that the collision is elastic, so total kinetic energy must be conserved , as follows:

        \Delta K = 0 \\ \\ \frac{1}{2} * m_{1} *v_{10} ^{2} = \frac{1}{2}* m_{1}  *v_{1f} ^{2}  + \frac{1}{2}* m_{2}  *v_{2f} ^{2} (3)

  • Rearranging , and simplifying common terms, we have:

        m_{1}* (v_{10} ^{2} -v_{1f} ^{2} ) = m_{2}  *v_{2f} ^{2} (4)

  • Replacing by the givens, doing some algebra and dividing (4) by (2), we find the following relationship:

        v_{10} + v_{1f} = v_{2f}

  • Replacing the expression above in (1), as m₂ = 2*m₁, we can find the value of v₁f, as follows:

       m_{1} * v_{10}  = m_{1} * v_{1f} +2*m_{1} * (v_{10} + v_{1f})\\ \\ -(m_{1} * v_{10}) = 3* m_{1} *v_{1f} \\ \\ v_{1f} = - \frac{v_{10} }{3}  = \frac{-17.1cm/s}{3} = -5.7 cm/s

7 0
3 years ago
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