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Vikentia [17]
3 years ago
11

If Ben invests $4500 at 4% interest per year, how much additional money must he invest at 5 1/2% annual interest to ensure that

the interest he receives each year is 4 1/2% of the total amount invested ?
Mathematics
1 answer:
pogonyaev3 years ago
5 0

Step \; 1: \; Assing \; variable \; for \; the \; unknown \; that \; we \; need \; to \; find.\\Let \; x \; be \; additional \; money \; invested

Step \; 2: \; Use \; the \; appropriate \; formula \; of \; simple \; interest \; set \; up \; an \; equation\\Interest \; earned \; each \; year = \; Amount \; invested \times annual \; rate \; of \; interest\\\\Amount \; invested \; in \; 4 \% \; rate \; of \; interest=\$4500\\Amount \; invested \; in \; 5\frac{1}{2}\% \; rate \; of \; interest= \$x\\Amount \; invested \; totally \; in \; 4\frac{1}{2}\% \; rate \; of \; interest = \$(4500+x)

Interest \; earned \; in \; 4\% \; interest \; rate\\ = \; 4500(4\%)=180\\Interest \; earned \; in \; 5\frac{1}{2}\% \; interest \; rate\\ = x(5\frac{1}{2}\%)=0.055x\\Interest \; earned \; totally \; in \; 4\frac{1}{2}\% \; interest \; rate = (4500+x)(4\frac{1}{2}\%)\\=0.045(4500+x)

\\\\So, \; the \; equation \; would \; be:\\180+0.055x=0.045(4500+x)

Step \; 1: \; Distribute \; 0.045 \; in \; the \; right \; side\\180+0.055x=202.5+0.045x\\\\Step \; 2: \; Subtract \; 0.045x \; and \; 180 \; on \; both \; sides \; to \; get \; x \; alone\\0.055x-0.045x=202.5-180\\\\Step \; 3: \; Combine \; Like \; Terms\\0.01x=22.5\\\\Step \; 4: Divide \; 0.01 \; on \; both \; sides\\\frac{0.01x}{0.01}=\frac{22.5}{0.01}\\\\Step \; 5: \; Simplifying \; fraction \; on \; both \; sides\\x=2250

\underline{Conclusion:}\\Ben \; should \; invest \; additional \; money \; of \; \$2250

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Answer:

x = √(3^125/ 5)

approx 2.9552445 * 10^29.

Step-by-step explanation:

2 log3 x + log3 5 =125​

log3 x^2 + log3 5 = 125

log3 (5x^2) = 125

3^125 = 5x^2

x^2 = 3^125/ 5

x = √(3^125/ 5)

This is a huge number

An approximation of it is 2.9552445 * 10^29.

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Step-by-step explanation:

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2 years ago
What is the answer, and how do I solve that equation in order to get my answer? I really want to get the hang of this.
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jarptica [38.1K]
Hmm

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4 0
3 years ago
Read 2 more answers
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