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3 years ago

13

Jennifer is ordering cake for her wedding reception. If one cake feed 18 people, how many cakes does she need to order for 150 p

eople?

1 answer:

ehidna [41]3 years ago

8 0

Answer:

8 1/3 cakes

Step-by-step explanation:

Step 1:

1 : 18 Ratio

Step 2:

1 : 18 = x : 150 Proportion

Step 3:

150 = 18x Multiply

Step 4:

150 ÷ 18 = x Divide

Answer:

x = 8 1/3

Hope This Helps :)

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J is the midpoint of CT<br> С<br> J<br> T<br> If:<br> CJ = 5x – 3 and<br> JT = 2x + 21<br> Find CT.

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Answer:

CT=37

Step-by-step explanation:

5x-3 = 2x+21

-2x

3x-3 = 21

+3

3x = 24

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× = 8

5(8) - 3 = 37

2(8) +21 =37

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Answer:

The function is $y~=~12 ~-~ 0.5 \cdot x$ .

The slope is $m=-0.5$ .

The y-intercept is $b=12$ .

Step-by-step explanation:

Our aim is to calculate the values <em>m</em> (slope) and <em>b</em> (y-intercept) in the equation of a line :

$y=mx+b$

We have the following data:

$\begin{array}{c|cccc}x&2&4&6&12\\y&11&10&9&6\end{array}$

To find the line of best fit for the points given, you must:

Step 1: Find $X\cdot Y$ and $X\cdot X$ as it was done in the table below.

Step 2: Find the sum of every column:

$\sum{X} = 24 ~,~ \sum{Y} = 36 ~,~ \sum{X \cdot Y} = 188 ~,~ \sum{X^2} = 200$

Step 3: Use the following equations to find <em>b</em> and <em>m</em>:

$\begin{aligned} b &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 36 \cdot 200 - 24 \cdot 188}{ 4 \cdot 200 - 24^2} \approx 12 \\ \\m &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 4 \cdot 188 - 24 \cdot 36 }{ 4 \cdot 200 - \left( 24 \right)^2} \approx -0.5\end{aligned}$

Step 4: Assemble the equation of a line

$\begin{aligned} y~&=~b ~+~ m \cdot x \\y~&=~12 ~-~ 0.5 \cdot x\end{aligned}$

The graph of the regression line is:

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