1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KiRa [710]
3 years ago
7

A professional boxer hits his opponent with a 1025 N horizontal blow that lasts 0.150 s. The opponent's total body mass is 116 k

g and the blow strikes him near his center of mass and while he is motionless in midair. Determine the following.
(a) impulse the boxer imparts to his opponent by this blow
kg · m/s
(b) the opponent's final velocity after the blow
m/s
(c) Calculate the recoil velocity of the opponent's 5.0-kg head if hit in this manner, assuming the head does not initially transfer significant momentum to the boxer's body.
m/s
Physics
1 answer:
mylen [45]3 years ago
5 0

Answer:

The impulse is  I  =  153.8 \ N \cdot s

The opponents velocity is  v=  1.33 m/s

The opponents head recoils velocity  v_r = 30.8 \ m/s

Explanation:

From the question we are told that

    The force of the blow is  F=  1025 \ N

    The duration of the blow is  t =  0.150

      The mass of the opponent is  m_o  =  116 \ kg

       The mass of the opponents head is  m_h  = 5 \ kg

The impulse the boxer imparts is mathematically represented as

         I  =  F *  t

substituting values

         I  =  1025 * 0.150

          I  =  153.8 \ N \cdot s

The impulse can also be mathematically evaluated as

         I  =  m_o * v

substituting values

          153.8  =  116 * v

          v=  \frac{153.8}{116}

          v=  1.33 m/s

The recoil velocity is mathematically represented as  

              v_r =  \frac{I}{m_h}

substituting values

                v_r =  \frac{153.8}{5}

                v_r = 30.8 \ m/s

You might be interested in
Which of the following accurately describes the behavior of these two mechanical waves when they intersect?
Lerok [7]
D because I learned this 2 years ago
5 0
3 years ago
Clouds dump around 100 billion gallons of water on rainforests each year. How much rain is evaporated from the rivers, lakes and
posledela
The correct answer is this one: "D) significantly more than 100 billion gallons ." Clouds dump around 100 billion gallons of water on rainforests each year. The amount of  rain is evaporated from the rivers, lakes and surface of rainforests each year is significantly more than 100 billion gallons<span> </span>
3 0
3 years ago
Read 2 more answers
Why are there only two elements in the first period of the periodic table?(1 point)
svetlana [45]

Answer:

because only two electrons can fit in the first orbit around the nucleus, and each period on the table is organized by number of orbits

5 0
3 years ago
Molds survive best in <br> A) warm, most<br> B) dry, cold <br> C) bright, sunny<br> places
lana66690 [7]
A..........................................
3 0
3 years ago
Read 2 more answers
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
3 years ago
Other questions:
  • A steel beam is rotated in a horizontal plane to provide the centripetal acceleration for
    13·1 answer
  • You blow across the open mouth of a test tube and produce the fundamental standing wave of the air column inside the test tube i
    11·2 answers
  • Which type of wave is allowing you to read this test question?
    12·1 answer
  • In what form does carbon return to the atmosphere after it is released from the burning of fossil fuels
    6·1 answer
  • The rate at which correct flows is measured in _?
    7·1 answer
  • Which statements does the Second Law of Thermodynamics support?
    13·1 answer
  • Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc
    8·1 answer
  • A watt is a unit of energy per unit time, and one watt (W) is equal to one joule per second ( J ⋅ s − 1 ) J⋅s−1) . A 40.0 W 40.0
    6·1 answer
  • How frequently do most coastal areas experience high tides?
    10·1 answer
  • speedy drives horizontally off a clif with a velocity of 15 m/s. he lands 30m from the base of the cliff. how high is the cliff?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!