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aleksandrvk [35]
3 years ago
13

You are generating traveling waves on a stretched string by wiggling one end. If you suddenly begin to wiggle more rapidly witho

ut appreciably affecting the tension, you will cause the waves to move down the string a. faster than before.b. at the same speed as before.c. slower than before.
Physics
1 answer:
german3 years ago
6 0

Answer:

Option as B is correct At the same speed as before

Explanation:

As we know the relation between speed of the wave and tension in string

The speed of wave in stretched string

ν = \sqrt{\frac{T}{\mu} }  

speed of wave is the directly proportional to the square root of tension as mentioned in question tension of string is unaffected when in linear mass density is constant,  so we can say that the  speed of wave will  be the same  

Option as B is correct At the same speed as before  

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sweet-ann [11.9K]

the Answer is 91  meters

3 0
3 years ago
A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, t
fredd [130]

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

F = m a\\\\a =\frac{F}{m}

We use movies and find lips

\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t

The moment is defined by

\to p = m v

The moment change

\Delta p = m v - m v_0

Let's replace the speeds in this equation

\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0  + F t - m v_0\\\\\Delta p = F t

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

5 0
3 years ago
An object that is falling has the following type(s) of energy. Ignore air resistance.
Anton [14]
Potential and kinetic
6 0
3 years ago
Read 2 more answers
A solid brass cylinder and a solid wood cylinder have the same radius and mass (the wood cylinder is longer). Released together
Lena [83]

Answer:

a. They will be tie

b. Win the wood cylinder

Explanation:

a.

The both cylinders will reach the bottom at the same time notice the relation in the equation in indepent of the length and both have the same radius and the same rotational inertia.

I=\frac{1}{2}*m*r^2

a=\frac{g*sin(\beta)}{1+I_{com}/m*r^2}

So both will be tie

b.

a_{brass}=\frac{g*sin(\beta)}{1+I_{brass}/m*r^2}=a_{wood}=\frac{g*sin(\beta)}{1+I_{wood}/m*r^2}

The acceleration of the wood cylinder is larger than the acceleration of the brass cylinder so the cylinder of wood will reach the bottom first

a_{brass}

So the wood win the race

6 0
3 years ago
Using the right amount of significant figures, calculate the answer to the following problem, 15.33879 + 15.555
MAXImum [283]

Answer:

there are 7 significant figures

Explanation:

15.33879+15.555

=30.89379

there are 7 significant figures

mark me as brainliest plyyzzz

7 0
4 years ago
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