Answer:
T= 1.71×10^{-3} sec= 1.71 mili sec
t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec
Explanation:
First of all we write equation for current oscillation in LC circuits. Note, the maximum current (I_0)= 5.5 mA is the amplitude of this function. Then, we continue to solve for the angular frequency(ω). Afterwards, we calculate the time period T. qo = maximum charge on capacitor. = 1.5× 10 ^− 6 C
a) I(t) = -ωqosin(ωt+φ)
⇒Io= ωqo
⇒ω= Io/qo
also we know that T= 2π/ω
⇒T= 
now putting the values we get
= 
= 1.71×10^{-3} sec
b) note that the time
it takes the capacitor to from uncharge to fully charged is one fourth of the period . That is


t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec
Answer:
The distance travel before stopping is 1.84 m
Explanation:
Given :
coefficient of kinetic friction 
Zak's speed 
Gravitational acceleration

Work done by frictional force is given by,




m
Therefore, the distance travel before stopping is 1.84 m
Explanation:
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through. The fault labeled "E" cuts through all three sedimentary rock layers (A, B,and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen and known of.
Answer:
a)54L/min
b)0.845
Explanation:
a) A x V=
where suffix 1,2,3 refers to the three pipes.
=27L/min+16L/min+11 L/min
=54L/min
b) A x V=54L/min =>
x v
d= 2 cm
x v = 54
v=
x
->
x
=27L/min =>
x 
= 1.3cm
x
= 27
=
x 
Next is to find the ratio of speed i.e 
x
/
x
=>

= 0.845
A=mgh
m=300g=0.3kg
g=9,81 m/s^2
h=10m
A=29.43J