Solubility at 100 °C = 480 g / 100 mL of solution =: saturated solution
The proportion 240 g / 50 mL is equal to the saturated ratio 480 g / 100 mL
Then, 240 g of sugar in 50 mL of boiling water will make a saturated solution.
Answer: saturated
Put the metal with the non-metal and use the charges to figure it out
First calculate the moles of CsOH.
moles CsOH = 0.217 M * 0.005 L = 0.001085 mol
We need 1 mole of HI per 1 mole of CsOH, therefore the
moles of HI needed is:
moles HI = 0.001085 mol
The volume required is therefore:
Volume = 0.001085 mol / 0.550 M
<span>Volume = 1.97x10^-3 L = 1.97 mL</span>
Answer:
ΔT = 0.78 °C
Explanation:
Given data:
Mass of Al = 9.5 g
Specific heat capacity of Al = 0.9 J/g.°C
Temperature change = ?
Heat added = 67 J
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
67 J = 9.5 g × 0.9 j/g.°C × ΔT
67 J = 85.5 j/°C × ΔT
ΔT = 67 J / 85.5 j/°C
ΔT = 0.78 °C