Hello!
First off, (-inf, -2) was half of the domain, so you were right on track, but almost there!
Since this function has a vertical asymptote at x = -2, any x-values that are equal to -2 cause the function to be undefined. So, we show that as (-∞, -2) because this function is a continuous function from that interval.
Since this function is also continuous from the interval -2 to ∞, we show that as the second part of our domain; written as (-2, ∞).
Remember that parentheses and brackets have different meanings when using them to state the domain/range of a function. Parentheses are used to <u>not</u> include that value, while brackets are used <u>to</u> include it.
In that case, we need to combine this two intervals using the "union" symbol, which is "U".
Therefore, the domain of the function is (-∞, -2) U (-2, ∞).
