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marta [7]
2 years ago
12

If VW≅VY, WX = s + 69, and XY = 4s, what is the value of s?

Mathematics
1 answer:
Maksim231197 [3]2 years ago
5 0

Answer:

s = 23

Step-by-step explanation:

Given VW ≅ VY then VX is a perpendicular bisector of WY then Δ WXY is isosceles with XY = WX , that is

4s = s + 69 ( subtract s from both sides )

3s = 69 ( divide both sides by 3 )

s = 23

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4 years ago
Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​
kykrilka [37]

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

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acc / acc / rej

solution (2)

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3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

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Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

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2 years ago
Math is a difficult subject for many students. Often, algebra is the worse, with “what do you mean solve for X? What is X”?! Mat
irakobra [83]
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