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3 years ago

Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air?

2 answers:

8 0

There’s quite a lot, one is gravity (or weight) which is the downward force, one is drag, which is the sideways force, and the last one is lift, which is the upwards force. Hope this helps!

vesna_86 [32]3 years ago

3 0

Answer:

Gravitational force

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When chalk is added to water and stirred what is formed

lianna [129]

The chalk will dissolve

5 0

3 years ago

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What is the molarity of a solution prepared by dissolving 0.217 mol of ethanol, C2H5OH, in enough water to make 100.0 mL of solu

sergeinik [125]

Answer: 2.17mol/L

Explanation:

C=n/V

n: 0.217mol

V: 100.0mL

1. Convert mL to L (100.0mL/1000 = 0.01L)

2. Put numbers into equation (C= 0.217/0.01L)

3. Molarity is 2.17mol/L

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3 years ago

Some patterns of electron configuration are listed below. In each case, [G] stands for a noble-gas core and n, m, or o stand for

Nonamiya [84]

Answer:

G]ns^2np^5 group 17 (p-block)

G]ns^2np^2 group 14 (p-block)

G]ns^2mf^14 group 16 (f-block)

Explanation:

The outermost electronic configuration of an element shows the group to which it belongs in the periodic table as shown above in the answer. In addition, to that, we can be able to know from its electronic configuration, whether the element is a metal or not.

For instance;

G]ns^2mf^14 is a rare earth metal, G]ns^2np^2 group 14 is a metalloid while G]ns^2np^5 group 17 is a nonmetal.

4 0

3 years ago

Given the following thermodynamic data, calculate the lattice energy of LiCl:

tiny-mole [99]

Answer:

$\boxed{\text{-862 kJ/mol}}$

Explanation:

One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s); U = ?

We must generate this reaction rom the equations given.

(1) Li(s) + ½Cl₂ (g) ⟶ LiCl(s); ΔHf° = -409 kJ·mol⁻¹

(2) Li(s) ⟶ Li(g); ΔHsub = 161 kJ·mol⁻¹

(3) Cl₂(g) ⟶ 2Cl(g) BE = 243 kJ·mol⁻¹

(4) Li(g) ⟶Li⁺(g) +e⁻ IE₁ = 520 kJ·mol⁻¹

(5) Cl(g) + e⁻ ⟶ Cl⁻(g) EA₁ = -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

(5) Li⁺(g) +e⁻ ⟶ Li(g) 520

(6) Li(g) ⟶ Li(s) -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s) -409

(8) Cl(g) ⟶ ½Cl₂(g) -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻ <u>+349</u>

Li⁺(g) + Cl⁻(g) ⟶ LiCl(s) -862

The lattice energy of LiCl is $\boxed{\textbf{-862 kJ/mol}}$ .

3 0

3 years ago

Equations can be balanced by using the half-reaction method. Which step should be completed immediately after finding the oxidat

Dovator [93]

After finding the oxidation states of atoms, you identify the half reactions (option c).

The half reactions are given by the change of the oxidation states of the atoms.

For example if Cu is in the left side with oxidation state 0 and in the other side with oxidation state 2+, then there you have a half reaction (oxidation reaction). And if you have O with oxidation state 0 in the left side and with oxidation state 2- in the right side, there you have other half reaction (reducing reaction).

8 0

4 years ago

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