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3 years ago

Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air?

2 answers:

8 0

There’s quite a lot, one is gravity (or weight) which is the downward force, one is drag, which is the sideways force, and the last one is lift, which is the upwards force. Hope this helps!

vesna_86 [32]3 years ago

3 0

Answer:

Gravitational force

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Which answer defines exothermic reaction?

kicyunya [14]

The answer which defines exothermic reaction is

a process in which energy is released as heat ( answer A)

Explanation

Exothermic reaction is a chemical reaction in which energy is released into environment in form of heat.

For example of exothermic reaction

Is a combustion reaction such as lighting a candle whereby oxygen react with wax to produce carbon (iV) oxide, water and heat.

8 0

4 years ago

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If you put a straw into a glass of water, the straw looks to be bent, although nothing has physically happened to the straw. The

scoray [572]

If you put a straw into a glass of water, the straw looks to be bent, although nothing has physically happened to the straw. The term that describes this property of light is called refraction.

So, the answer would be: Refraction

5 0

3 years ago

Read 2 more answers

A reaction A(aq)+B(aq)↽−−⇀C(aq) has a standard free‑energy change of −4.51 kJ/mol at 25 °C.

SVEN [57.7K]

Answer:

(a) [A] = 0.13 M, [B]= 0.23 M and [C] = 0.17 M.

(b) Option B.

Explanation:

The reaction given:

A(aq) + B(aq) ⇄ C(aq) (1)

Initial: 0.30M 0.40M 0M (2)

Equilibrium: 0.3 - x 0.4 - x x (3)

The equation of Gibbs free energy of the reaction (1) is the following:

$\Delta G^{\circ} = - RTLn(K_{eq})$ (4)

where ΔG°: is the Gibbs free energy change at standard conditions, R: is the gas constant, T: is the temperature and $K_{eq}$ : is the equilibrium constant

(a) To calculate the concentrations of A, B, and C at equilibrium, we need first determinate the equilibrium constant using equation (4), with ΔG°=-4.51x10³J/mol, T=25 + 273 = 298 K, R=8.314 J/K.mol:

$K_{eq} = e^{-\frac{\Delta G^{\circ}}{RT}} = e^{-\frac{-4.51\cdot 10^{3} J/mol}{8.314 J/K.mol \cdot 298 K}} = 6.17$ (5)

Now, we can calculate the concentrations of A, B, and C at equilibrium using the equilibrium constant calculated (5):

$K_{eq} = \frac{[C]}{[A][B]} = \frac{x}{(0.3 - x)(0.4 - x)}$ (6)

Solving equation (6) for x, we have two solutions x₁=0.69 and x₂=0.17, and by introducing the solution x₂ into equation (3) we can get the concentrations of A, B, and C at equilibrium:

$[A] = 0.3 - x_{2} = 0.3 - 0.17 = 0.13 M$

$[B] = 0.4 - x_{2} = 0.4 - 0.17 = 0.23 M$

$[C] = x = 0.17 M$

Notice that the solution x₁=0.69 would have given negative values of the A and B concentrations.

(b) If the reaction had a standard free-energy change of +4.51x10³J/mol, the equilibrium constant would be:

$K_{eq} = e^{-\frac{\Delta G^{\circ}}{RT}} = e^{-\frac{4.51\cdot 10^{3} J/mol}{8.314 J/K.mol \cdot 298 K}} = 0.16$

By solving the equation (6) for x, with the equilibrium constant calculated, we can get again two solutions x₁ = 6.9 and x₂= 0.017, and by introducing the solution x₂ into equation (3) we can get the concentrations of A, B, and C at equilibrium:

$[A] = 0.3 - x_{2} = 0.3 - 0.017 = 0.28 M$

$[B] = 0.4 - x_{2} = 0.4 - 0.017 = 0.38 M$

$[C] = x = 0.017 M$

Again, the solution x₁=6.9 would have given negative values of the A and B concentrations.

Hence, the correct answer is option B: there would be more A and B but less C.

I hope it helps you!

7 0

3 years ago

Why do certain chemicals make the freezing process slower by interrupting interactions between water molecules? please go more i

lapo4ka [179]

Answer:

Solutions made by dissolving something in water - typically, the more concentrated the solution, the lower the freezing point because the solute molecules disrupt the ability of water molecules to interact with one another and to form organized structures as the temperature is lowered.

4 0

3 years ago

How many moles are in 85.0 grams of water

alexgriva [62]

To convert from grams to moles, you must divide the given mass by the molecular weight. If this is so, then:

Water ≈ 18.02 grams/mol.

85.0 g/ 18.02 g/mol ≈ 4.72 moles

3 0

4 years ago