The answer is: distance is 3 km, displacement is 2.24 km.
Distance is total length: 1 km east + 1 km south + 1 km east again = 3 km
Displacement is the hypotenuse of the right triangles which sides are 1 km east and 2 km south. According to the Pythagorean theorem:
a² + b² = c²
1² + 2² = c²
1 + 4 = c²
5 = c²
c = √5
c = 2.24 km
Answer:
ITS THE LAST ONE AND THE SECOND ONE
Explanation:
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
Group 2 contains soft, silver metals that are less metallic in character than group 1 elements. There is a fairly strong conductivity trend within each row, left to right, and a weaker trend top to bottom. The elements in group 2 are moderately good conductors, while the elements on the right are very poor conductors. <span>As you move vertically between rows, conductivity decreases overall, but slowly.
Group 2 have a generally low electronegativity. Electronegativity decreases moving left and down across the table.</span>
