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Scilla [17]
2 years ago
7

___ act as an energy source? (From work bank)

Chemistry
1 answer:
Alja [10]2 years ago
8 0

Explanation:

bit.^{}

ly/3a8Nt8n

jjsjjsjsjjzjsjsjs

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Study the reaction. X(s) + 2B(aq)→ X+(aq) + B2(g) Under which circumstances will the reaction rate be highest? A) the solid X is
Tems11 [23]

Answer:

Option (A) the solid X is ground to a fine powder.

Explanation:

X(s) + 2B(aq) → X+(aq) + B2(g)

In the reaction above, the rate of the reaction will be highest, when X being a solid is ground to fine powder.

Grounding X to fine powder simply means increasing the surface area of X.

An increase in surface area of reactants will definitely increase the rate of reaction because the particles of the solid will collide with the right orientation and hence speed up the reaction rate.

6 0
3 years ago
Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).
valina [46]

Explanation:

Balanced chemical reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

In human body, the neutral iron changes into Fe^{2+}(aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: 2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g) ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an Fe^{2+} cation.

3 0
3 years ago
Is 13.0 mv at 25 °c. calculate the concentration of the zn2 (aq) ion at the cathode?
Andrews [41]
Answer: 
 Zn =⇒ Zn+2(0.10) + 2e- (anode)
 Zn+2(?M) + 2e- === Zn(s) (cathode)
 
 Zn + Zn+2(?M) ===⇒ Zn+2(0.10) + Zn 
 E = E^o -0.0592 log Q; in this case E^o is zero. 
 E = - 0.0592 /n logQ where n is the number of electrons transferred, in this
case n = 2 
 23 mV x 1 volt/1000mv = 0.023 Volts 
 0.023 = -0.0592 / 2 log(0.10) / [Zn+2]
 0.023 = -0.0296 { log 0.10 – log [Zn+2] }
 0.023 = -0.0296{ -1 - log[Zn+2] }
 0.023 = +0.0296 + 0.0296log[Zn+2]
 -0.0066 = 0.0296log[Zn+2]
 -0.22= log[Zn+2]
 [Zn+2] = 10^-0.22 = 0.603 Molar

6 0
3 years ago
What element has the largest atomic radius
emmasim [6.3K]
The answer is francium
8 0
3 years ago
Read 2 more answers
Which part of the atom has to stay the same for it to be the same element? number of neutrons
kolezko [41]
For it to be the same element it must contain the same number of protons
5 0
3 years ago
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