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jasenka [17]
3 years ago
6

How many grams of H20 will be produced by 18g H2

Chemistry
1 answer:
AURORKA [14]3 years ago
8 0

Answer:

160.86 g to the nearest hundredth.

Explanation:

H2 + O  ---> H2O

2.016 g H2 produces 18.016 g H2O

1g      ..    ..   ..   ..   ..    18.016 / 2.016 g H2O

18g   ..   ..   ..  ..  .. . .     (18.016 * 18) / 2.016 g H2O.

= 160.86 g.

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For each pair below, select the sample that contains the largest number of moles. Pair A 2.50 g O2 2.50 g N2
raketka [301]

Answer:

Explanation:

Pair  2.50g of O₂ and 2.50g of  N₂

The atoms sample with the largest number of moles since the masses are the same would be the one with lowest molar mass according the the equation below:

Number of moles = \frac{mass }{molarmass}

Atomic mass of O = 16g and N = 14g

Molar mass of O₂ = 16 x 2 = 32gmol⁻¹

Molar mass of N₂ = 14 x 2 = 28gmol⁻¹

Number of moles of O₂ = \frac{2.5}{32} = 0.078mole

Number of moles of N₂ = \frac{2.5}{28} =  0.089mole

We see that N₂ has the largest number of moles

4 0
3 years ago
Read 2 more answers
Una muestra de 258.4 g de etanol (C2H5OH) se quemó en una bomba calorimétrica
Ilia_Sergeevich [38]

Answer:

Explanation:

Unclear question.

I infer you want a clear rendering, which reads;

A 258.4 g sample of ethanol (C2H5OH) was burned in a calorimetric pump using a Dewar glass. As a consequence, the water temperature rose to 4.20 ° C.

If the heat capacity of the water and the surrounding glass was 10.4 kJ / ° C, calculate the heat of combustion of one mole of ethanol.

4 0
4 years ago
If irons temperature goes from 50c to 75c in a 20g sample, how many joules of heat were used?
Marina CMI [18]

Answer:

Option D. 230 J

Explanation:

We'll begin by calculating the temperature change of the iron. This can be obtained as follow:

Initial temperature (T₁) = 50 °C

Final temperature (T₂) = 75 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 75 – 50

ΔT = 25 °C

Thus, the temperature change of the iron is 25 °C.

Finally, we shall determine the amount of heat energy used. This can be obtained as follow:

Mass (M) = 20 g

Change in temperature (ΔT) = 25 °C

Specific heat capacity (C) = 0.46 J/gºC

Heat (Q) =?

Q = MCΔT

Q = 20 × 0.46 × 25

Q = 230 J

Thus, the amount of heat used was 230 J

3 0
3 years ago
Describe the modem system of cassification,
yaroslaw [1]

Answer: The system classifies organisms into eight levels: domain, kingdom, phylum, class, order, family, genus, and species.

Explanation:

The scientific name given to an organism is based on binomial nomenclature.

5 0
3 years ago
What is the molar mass of 56.75 g of gas exerting a pressure of 2.87 atm on the walls of a 5.29 l container at 230 k?
laiz [17]
We first need to find the number of moles of gas in the container 
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation 
290 802.75 Pa x  5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
the molar mass = mass present / number of moles
molar mass of gas = 56.75 g / 0.804 mol 
therefore molar mass is 70.6 g/mol 
8 0
3 years ago
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