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3 years ago

For which of the following measures is Earth's the highest compared to the other planets in our Solar System?

1 answer:

6 0

Missing question:
a) mass.
b) diameter.
c) distance from the Sun.
d) density.
Answer is: d) density.
Earth has the highest density of all eight planets in the Solar System, density of the Earth is 5.514 g/cm³.
The four inner planets, closest to the Sun, are all terrestrial planets, which means they are composed of silicate rocks and metals and four outer planets are gas giants, they are composed of hydrogen, helium and water.
Earth is third planet from the Sun.

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sugar dissolving in water was a good example of what kind of change? A. physical B. chemical C. Electical

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Explanation:

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3 years ago

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Gelneren [198K]

I’ve got 2 reasons: life on campus should imitate real life and restrictions will be in the way of that, we all have the right to have freedom

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3 years ago

As ice melts from a solid to a liquid, A) entropy increase

Dovator [93]

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3 years ago

A compound with the empirical formula CH2 has a molar mass of 126g/mol. What is the molecular formula for this compound?

stellarik [79]

Answer: C10H20

Explanation:

C=12

H=1

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Molecular formula

C10H20

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3 years ago

Read 2 more answers

A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill

LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

$BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)$

$Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)$

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

$\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%$

This means in 10.0 g, we have a total of:

$m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g$ of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

$\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%$

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

if this number is equal to 6.595 g, we have a pure sample of barium chloride;
if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.

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3 years ago