Answer:
4.87g
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Mass of solution = 0.35kg
Molality = 0.238 m
Mass of NaCl =..?
Step 2:
Determination of the number of mole of NaCl in the solution.
Molality of a solution is simply defined as the mole of solute per unit kg of the solvent. It is given as:
Molality = mol of solute /mass of solvent (kg)
With the above formula, we calculate the mole of NaCl present in the solution as follow:
Molality = mol of solute /mass of solvent (kg)
0.238 = mol of NaCl /0.35
Cross multiply
mol of NaCl = 0.238 x 0.35
mol of NaCl = 0.0833 mol
Step 3:
Determination of the mass of NaCl in 0.0833 mol of NaCl.
This is illustrated below:
Number of mole NaCl = 0.0833 mol
Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol
Mass of NaCl =..?
Mass = number of mole x molar Mass
Mass of NaCl = 0.0833 x 58.5
Mass of NaCl = 4.87g
Therefore, 4.87g of NaCl is contained in the solution.
Hey there!
Molar mass Na2SO4 = 142.04 g/mol
Number of moles:
n = m / mm
n = 25 / 142.04
n = 0.176 moles of Na2SO4
Therefore, use the Avogadro constant
1 mole Na2SO4 ------------------- 6.02x10²³ molecules
0.176 moles Na2SO4 ------------ molecules ??
0.176 x ( 6.02x10²³ ) / 1
=> 1.059x10²³ molecules of Na2SO4
hope this helps!
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<h3>
What are Isomers ?</h3>
Isomers are compounds which have same empirical formula , same number of atoms are present but they have difference in arrangement if the atoms.
It is given that
There are four cis, trans isomers for 2-isopropyl-5-methylcyclohexanol
the cis, trans designations of the substituents are made relative to the oh group
The image is attached with this answer.
To know more about Isomers
brainly.com/question/13422357
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Table slat has a low melting pointy while mercury has a high one
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The answer is [OH⁻] = 1 x 10⁻⁴.
[OH⁻] = H₂O ÷ [H₃O⁺]
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻¹⁰
[OH⁻] = 10⁻⁴
