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Rama09 [41]
3 years ago
9

What is the electron structure of sodium

Chemistry
2 answers:
yarga [219]3 years ago
8 0
Electron structure of sodium:
₁₁Na: 1s²2s²2p⁶3s¹
Elan Coil [88]3 years ago
7 0

Answer:

Na: 1s²2s²2p⁶3s¹

Explanation:

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3 years ago
What is the molar concentration (molarity) of 1.0 mol of KCl dissolved in 750 mL of
Nikolay [14]

Answer:

Molarity is moles per liter. You have one mole in 0.750 liters

Explanation:

8 0
2 years ago
What is the balanced form of the chemical equation shown below?
Tanzania [10]
B. 1, 1, 1, 2
Explanation:
You only need to balance the NaNO3 on the right. Since there is 2 NO3 on the left, you need to put a 2 in front of the NaNO3 on the right. Everything else is already balanced so the only coefficient needed is 2 in front of the NaNO3.
7 0
2 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
2 years ago
Which of the following yields a basic solution when dissolved in water? I. Nh3 ii. Na2o iii. Lioh iv. P4o10
emmainna [20.7K]

<u>Answer:</u> The correct answer is Option 1, Option 2 and Option 3.

<u>Explanation:</u>

A base is defined as the substance which releases hydroxide ion when dissolved in water.

For the given options:

  • <u>Option 1:</u>  NH_3

When ammonia is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

NH_3+H_2O\rightarrow NH_4OH

  • <u>Option 2:</u>  Na_2O

When sodium oxide is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

Na_2O+H_2O\rightarrow 2NaOH

  • <u>Option 3:</u>  LiOH

When lithium hydroxide is dissolved in water, it produces aqueous lithium hydroxide which forms a basic solution.

LiOH+H_2O\rightarrow LiOH(aq.)

  • <u>Option 4:</u>  P_4O_{10}

When phosphorus pentoxide is dissolved in water, it produces phosphoric acid which forms an acidic solution.

P_4O_{10}+6H_2O\rightarrow 4H_3PO_4

Hence, the correct answer is Option 1, Option 2 and Option 3.

8 0
3 years ago
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