Answer:
The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the true proportion of all voters in the state who favor approval is (0.4384, 0.5050).
Set up a proportion.
pounds / milligrams of medicine
195/279 = 130/x
195x = 279 times 130
195x =36,270
x = 36,270/195
x = 186
A patient weighing 130 pounds needs 186 milligrams of medicine.
The answer is 22.3 i hope that helped
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