25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A
Artyom0805 [142]
Answer:
(i) U' = Φ
(ii) A∩A' = Φ
(iii) A – ( B U C) = {5,7,9}
(iv) A' U ( B U C ) = {2,4,6,8,10}
(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}
Step-by-step explanation:
Answer:
idk
Step-by-step explanation:
we are nt on that yet
Here's a scenario that you can edit to your own advantage. You own a shirt shop. Each shirt sells for 15 dollars, and to make profit annually you need to sell $62,365 worth of shirts. If you've sold 2,000 shirts so far, how many shirts do you need to meet your quota. How many shirts on average per month would you have to sell?
Answer:
To the nearest integer, the square root of 39 would be 6.
Step-by-step explanation:
To find the answer, look at the perfect squares on either side of 39. Lower than it would be 36 and the next highest would be 49. Since it is closer to 36, we can estimate that the answer is 6.
