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Radda [10]
3 years ago
13

Solve for c: E=mc^2

Mathematics
2 answers:
Katen [24]3 years ago
8 0

Answer: E=mc^2

E/m=c^2

Square root of e/m = c

C = square root symbol e/m

Yw :)

Svetradugi [14.3K]3 years ago
4 0
E=mc²
E/m = c²
c = sqrtE/m
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blondinia [14]

Answer:

the surface area of the rectangle is 40

the surface area of the triangles is 6

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Step-by-step explanation:

8 0
3 years ago
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Solve This Probpem -5x+12=32
laiz [17]
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6 0
4 years ago
A job fair was held at the Student Union. 25% of the students who attended received job offers. Of all of the students at the jo
vovangra [49]

Answer:

A) Both events are not independent.

B) Both events are not mutually exclusive

C) 8.33%

D) 80%

Step-by-step explanation:

A) Both events are not independent. This is because, If B occurs it means that it is very likely that J will occur as well.

B) Both events are not mutually exclusive. This is because it is possible for both events J and B to occur at the same time.

C) we want to find the probability that Joe who is not a business student will receive the job offer.

This is;

P(J|Not B) = P(J & Not B)/P(Not B)

Now,

P(J & Not B) = P(J) – (P(B) × P(J | B))

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40% were from the College of Business. Thus;

P(B) = 0.4

Among the business students, 50% received job offers. Thus;

P(J|B) = 0.5

Thus;

P(J & Not B) = 0.25 - (0.4 × 0.5)

P(J & Not B) = 0.25 - 0.2

P(J & Not B) = 0.05

Since P(B) = 0.4

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P(J|Not B) = 0.05/0.6

P(J|Not B) = 0.0833 = 8.33%

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P(B | J) = P(B & J)/P(J)

P(B & J) = (P(B) × P(J | B)) = (0.4 × 0.5) = 0.2

P(B | J) = 0.2/0.25

P(B | J) = 0.8 = 80%

5 0
3 years ago
The answer and how to get the answer
Advocard [28]

Answer: Answer is below (decimal form is 3.3)

Step-by-step explanation: Explanation is below.

5 0
3 years ago
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Karolina [17]

Answer:

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3 years ago
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