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never [62]
3 years ago
11

A boy and his dog are running. The dog has a mass of 20kg and the boy has a mass of 45kg.

Physics
1 answer:
Ad libitum [116K]3 years ago
4 0

Answer:

Explanation:

mass of boy =m1=45 kg

mass of dog =m2=20kg

the speed of boy=3 m/s

the speed of dog =3 m/s

K.E of boy  

K.E=1/2mv²

K.E=1/2(45)(3)²

K.E=202.5 J

K.E of dog

K.E=1/2mv²

K.E=1/2(20)(3)²

K.E=90 J

now the new speed of dog is 6 m/s

therefore new K.E of dog is

K.E=1/2(20)(6)²

K.E=360 j

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3 years ago
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Pressure, P = 32666.66 Pa

Explanation:

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P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{50\times 9.8}{0.015}\\\\P=32666.66\ Pa

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7 0
3 years ago
a bowling ball has a mass of 6 kilograms. a tennis ball has a mass of 0.06 kilogram. how much inertia does the bowling ball have
Andreyy89

Answer:

100 times

Explanation:

Since inertia is directly proportional to the mass of an object, the higher the mass the higher the inertia. In this case, 6 Kg is 100 times heavier than 0.06 Kg to imply The bowling ball  has 100 times more inertia than the tennis  ball because it has 100 times more mass

5 0
3 years ago
Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe
iris [78.8K]

Answer:

Explanation:

1.  V_{x} = V_{0} * cos\alpha ⇒ 16*cos32 ≈ 13.6 m/s (13.56)

2. V_{y} = V_{0} * sin\alpha ⇒ 16* sin32 ≈ 9.4 m/s

3. y_{max} = \frac{v_{0}^2*sin^2\alpha}{2g}= \frac{16^2*sin^232}{2*9.8} (the g (gravity) depends on the country but i'll take the average g which is 9.2m/s^2)

y_{max} ≈ 3.6677+1.5 ≈ 5.2m

4.  x_{max} = \frac{v_{0}^2*sin(2\alpha)}{g}=\frac{16^2*sin(2*32)}{9.8} ≈ 23.5m (23.47)

5. -

answer 4 could be wrong, not certain about that one and i don't know 5

3 0
3 years ago
A spring with a spring constant of 1200 N/m has a 55-g ball at its end. The energy of the system is 5.5J. What is the amplitude
Pepsi [2]
The energy of the system is E=5.5 J. This energy is the  same at every moment of the oscillation. When the stretch x of the spring is maximum (so, when the stretch is equal to the amplitude: x=A) the velocity of the spring is zero, so all this energy is just elastic potential energy of the spring:
E= \frac{1}{2}kA^2
From which we find
A= \sqrt{ \frac{2E}{k} }= \sqrt{ \frac{2 \cdot 5.5 J}{1200 N/m} }=0.096 m
4 0
3 years ago
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