Answer:
hello your question lacks some data and required diagram
G = 77 GPa, т all = 80 MPa
answer : required diameter = 252.65 * 10-^3 m
Explanation:
Given data :
force ( P ) = 660 -N force
displacement = 15 mm
G = 77 GPa
т all = 80 MPa
i) Determine the required diameter of shaft BC
considering the vertical displacement ( looking at handle DC from free body diagram )
D' = 0.3 sin∅ , where D = 0.015
hence ∅ = 2.8659°
calculate the torque acting at angle ∅ of CD on the shaft BC
Torque = 660 * 0.3 cos∅
= 660 * 0.3 * cos 2.8659 = 198 * -0.9622 = 190.5156 N
hello attached is the remaining part of the solution
Lipids and <span>Polysaccharides r the answers hoped i helped</span>
Explanation:
Formula to determine the critical crack is as follows.
![K_{IC} = \gamma \sigma_{f} \sqrt{\pi \times a}](https://tex.z-dn.net/?f=K_%7BIC%7D%20%3D%20%5Cgamma%20%5Csigma_%7Bf%7D%20%5Csqrt%7B%5Cpi%20%5Ctimes%20a%7D)
= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and, ![\sigma_{f} = 570 \times \frac{3}{4}](https://tex.z-dn.net/?f=%5Csigma_%7Bf%7D%20%3D%20570%20%5Ctimes%20%5Cfrac%7B3%7D%7B4%7D)
= 427.5
Hence, we will calculate the critical crack length as follows.
a = ![\frac{1}{\pi} \times (\frac{K_{IC}}{\sigma_{f}})^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Cpi%7D%20%5Ctimes%20%28%5Cfrac%7BK_%7BIC%7D%7D%7B%5Csigma_%7Bf%7D%7D%29%5E%7B2%7D)
= ![\frac{1}{3.14} \times (\frac{24.1}{427.5})^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3.14%7D%20%5Ctimes%20%28%5Cfrac%7B24.1%7D%7B427.5%7D%29%5E%7B2%7D)
= ![10.13 \times 10^{-4}](https://tex.z-dn.net/?f=10.13%20%5Ctimes%2010%5E%7B-4%7D)
Therefore, largest size is as follows.
Largest size = 2a
= ![2 \times 10.13 \times 10^{-4}](https://tex.z-dn.net/?f=2%20%5Ctimes%2010.13%20%5Ctimes%2010%5E%7B-4%7D)
= ![20.26 \times 10^{-4}](https://tex.z-dn.net/?f=20.26%20%5Ctimes%2010%5E%7B-4%7D)
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is
.