All categories

3 years ago

If a and b are two digits, then the following fraction

Mathematics

2 answers:

Andrews [41]3 years ago

6 0

Answer:

B. 1010

Step-by-step explanation:

Simplify:

(ab0+ab0ab) ÷ (ab) - 1

Note that:

ab = 10a +b
ab0 = 10* (10a + b) = 10ab
ab0ab = 1000ab + ab = 1001 ab

Therefore:

(ab0+ab0ab) ÷ (ab) - 1 =
(10ab + 1001ab) ÷ (ab) - 1 =
(1011ab) ÷ (ab) - 1 =
1011 - 1=
1010

Correct choice is B.1010

viva [34]3 years ago

3 0

The answer to this is B.

You might be interested in

Find the quotient of 2.632 · 104 and 2 · 10-7.

faust18 [17]

2.632 x 10^4 ÷ 2 x 10-7 =

1.316 x 10^11

5 0

4 years ago

Read 2 more answers

A bakery sold a total of 500 cupcakes in a day, and 5% of them were vanilla flavored. How many of the cupcakes sold that day wer

topjm [15]

25 were vanilla
500 divided by 100 is 5 meaning that one percent is 5 and 5x5 is 25

5 0

3 years ago

Read 2 more answers

Simplify the product using the distributive property. (-4h +2)(3h +7)

Alekssandra [29.7K]

Answer:

A. -12h² - 22h + 14

Step-by-step explanation:

(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc

= (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)

= -12h² -28h +6h +14

= -12h² -22h +14 . . . . . . . . collect terms

3 0

3 years ago

If there are 48 boys and 64 girls and the teachers decided to put them each in in equal rows only boys or girls will be in each

german

Answer: 16

Step-by-step explanation:

The question seeks to know the largest number of people that can sit in each row.

To answer this, find the Highest Common Factor of the numbers 48 and 64.

Factors of 48 ⇒ 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48

Factors of 64 ⇒ 1, 2, 4, 8, 16, 32 and 64

Because the teacher wants the rows to be equal with either only boys or only girls sitting in them, the highest number of people that can sit in a row will be 16.

There will be 7 rows in total.

Boys ⇒ 48/ 16 = 3 rows

Girls ⇒ 64/16 = 4 rows

5 0

3 years ago

Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil

KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

= 6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

= 9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

= 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

= 4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

= 4.5 days to get to the next pond.

3 0

3 years ago