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KatRina [158]
3 years ago
11

Use the electronegativities in the periodic table above to determine which bonding pair forms polar covalent bonds.

Chemistry
1 answer:
VikaD [51]3 years ago
3 0
image plz i need that to answer question
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. Which law of motion relates the action of a stretched rubber band
storchak [24]

Answer:

newtons 3rd law of motion

Explanation:

3 0
3 years ago
1.65g of zinc is used to make 8g of zinc iodide. How much iodine is required for this reaction?
creativ13 [48]

Answer:

6.45 g of iodine, I₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Zn + I₂ —> ZnI₂

Next, we shall determine the mass of Zn and I₂ that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Zn = 65 g/mol

Mass of Zn from the balanced equation = 1 × 65 = 65 g

Molar mass of I₂ = 127 × 2 = 254 g/mol

Mass of I₂ from the balanced equation = 1 × 254 = 254 g

SUMMARY:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Finally, we shall determine the mass of f I₂ needed to react with 1.65 g of Zn. This can be obtained as follow:

From the balanced equation above,

65 g of Zn reacted with 254g of I₂.

Therefore, 1.65 g of Zn will react with = (1.65 × 254)/65 = 6.45 g of I₂.

Thus, 6.45 g of iodine, I₂ is needed for the reaction.

4 0
3 years ago
A 100.0 mL sample of 0.10 M Ca(OH)2 is titrated with 0.10 M HBr. Determine the pH of the solution after the addition of 300.0 mL
Vera_Pavlovna [14]

Answer : The correct option is, (C) 1.7

Explanation :

First we have to calculate the moles of Ca(OH)_2 and HBr.

\text{Moles of }Ca(OH)_2=\text{Concentration of }Ca(OH)_2\times \text{Volume of solution}=0.10M\times 0.1L=0.01mole

\text{Moles of }HBr=\text{Concentration of }HBr\times \text{Volume of solution}=0.10M\times 0.3L=0.03mole

The balanced chemical reaction will be:

Ca(OH)_2+2HBr\rightleftharpoons CaBr_2+2H_2O

0.01 mole of Ca(OH)_2 dissociate to give 0.01 mole of Ca^{2+} ion and 0.02 mole of OH^- ion

and

0.03 mole of HBr dissociate to give 0.03 mole of H^+ ion and 0.03 mole of Br^- ion

That means,

0.02 moles of OH^- ion  neutralize by 0.02 moles of H^+ ion.

The excess moles of H^+ ion = 0.03 - 0.02 = 0.01 mole

Total volume of solution = 100 + 300 = 400 ml = 0.4 L

Now we have to calculate the concentration of H^+ ion.

\text{Concentration of }H^+=\frac{\text{Moles of }H^+}{\text{Total volume}}

\text{Concentration of }H^+=\frac{0.01mole}{0.4L}=0.025M

Now we have to calculate the pH of the solution.

pH=-\log [H^+]

pH=-\log (0.025M)

pH=1.7

Therefore, the pH of the solution is, 1.7

5 0
3 years ago
A mover packs books, CDs, and DVDs into a moving box. If the box contains 6.5 kg of books, 1.5 kg of CDs, and 2.0 kg of DVDs, wh
IrinaVladis [17]

Answer:

\text{Mass percentage}=\frac{\text{Mass of the substance}}{\text{Total mass}}\times 100

Given: Mass of books = 6.5 kg

Mass of CD's = 1.5 kg

Mass of DVD's = 2.0 kg

Total mass = 6.5 kg + 1.5 kg + 2.0 kg = 10 kg

\text {Mass percentage of books}=\frac{6.5kg}{10kg}\times {100}=65\%

\text {Mass percentage of CD's}=\frac{1.5kg}{10kg}\times {100}=15\%

\text {Mass percentage of DVD's}=\frac{2.0kg}{10}\times {100}=20\%

7 0
3 years ago
Read 2 more answers
I need help with this
natulia [17]

Answer:

129 units cubed

Explanation:

There are ten spaces between 120 and 130, so we can infer that each line represents a change in volume of 1 unit. The volume of the substance in the graduated cylinder looks like it's 1 under 130, so its volume is 129 units.

Hopefully this was helpful! :)

6 0
3 years ago
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