First, we write the balanced equation for this reaction:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:

Moles = volume (in L) * molarity

We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:

M₁V₁ = 2M₂V₂

V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L

The volume required is 173.6 mL

5 0

3 years ago

You measure the mass of a model car to be 230 grams.The actual mass is 218 grams .what is your percent error

LenKa [72]

Your percent is 5.50458716

8 0

4 years ago

Which of the following series of isoelectronic ions (Mg²⁺, N³⁻, F⁻, Si⁴⁺) has the ionic radii in order of largest to smallest? A

Rom4ik [11]

Answer:

Option (d) is correct

N³⁻ > F⁻ > Mg²⁺ > Si⁴⁺

Explanation:

Total electrons for all the species = 10

So these are <u>iso electronic</u> with each other.

We know

Ionic radii ∝ $\frac{Magnitude of Negative Charge}{Magnitude of Positive Charge}$

Si⁴⁺ has 14 protons and 10 electrons
Mg²⁺ has 12 protons and 10 electrons
N³⁻ has 7 protons and 10 electrons
F⁻ has 9 protons and 10 electrons

Iso electronic species with greatest number of protons have small size and vice versa.
So Si⁺⁴ have smallest size and N³⁻ have largest in size

4 0

4 years ago