Correct Answer: option C:The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.
Reason:
Both of the above molecules contain double bonds. They are characterized by sp^2 hybridization. Also, they possess a trigonal planar geometry. In trigonal planar system, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree.
Answer:
In the quantum-mechanical model of an atom, electrons in the same atom that have the same principal quantum number (n) or principal energy level are said to occupy an electron shell of the atom. Orbitals define regions in space where you are likely to find electrons.
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
You should use Avogadro’s number for the conversion, because Avogadro’s Law states that there are 6.02 x 10^23 atoms per 1 mol of that substance.
Add 2 that’s why and I said if
