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wel
3 years ago
6

The special proteins prevent a or b

Chemistry
2 answers:
In-s [12.5K]3 years ago
8 0

Answer:

C'est fini sous la lettre A. Ice crystals from forming inside it's body

xenn [34]3 years ago
6 0

Answer: a

Explanation:

this is common sense

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The maximum speed limit on a highway is 55 miles per hour. What is that speed in meters per second? (mi = 1.609 km)
Slav-nsk [51]

Answer:

24.5872 meters per second

Rouned 24.6 or 25

5 0
3 years ago
How many molecules of CrCl₃ are produced when 2.89 moles of CuCl₂ react? *<br> 2Cr+3CuCI2-2CrCI3+3Cu
juin [17]

Explanation:

The reaction is CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

.

Thus, 2 moles of HCl reacts with one mole of calcium carbonate to produce one mole each of calcium chloride, water and carbon dioxide respectively.

Hence, 3 moles of HCl will react with excess of calcium carbonate to produce 3×

2

1

=1.5 mol of carbon dioxide

3 0
3 years ago
An unknown solution has a pH of 2. How would you classify this solution?
devlian [24]
Acidic because anything over a ph of 7 would be basic but anything below 7 would be acid and if it has a ph of 7 it would be neutral....Hope I helped
7 0
3 years ago
In this simulation what do you think the bread and cheese separately represent, the atom or the molecule?
Svetllana [295]

Answer:

the atom

Explanation:

The bread and cheese separately represent the atom because both bread and cheese are different from one another and we cannot assume it as a molecule because molecules formed when the group of atoms combine together by making bonds with each other and we know that bread and cheese did not make bonds with each other, they only attached, so we called them atoms not molecule.

8 0
3 years ago
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
4 years ago
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