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<span>Answer:
The total anion concentration = 6.0 + 2x12.0 + 3.0 = 33.0mEq/L</span>
Answer:
44.2 L
Explanation:
Use Charles Law:
We have all the values except for V₂; this is what we're solving for. Input the values:
- make sure that your temperature is in Kelvin
From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:
Therefore, V₂ = 44.2 L
It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.
Answer:
The answer to the question is
The mass of the water in the container, assuming that all the heat lost by the copper is gained by the water is 116.23 grams
Explanation:
To solve this we list out the variables thus,
mass of copper = 110g
specific heat capacity of copper = 0.20 j/C g
Initial temperature of copper = 82.4 C
Final temperature of copper and water = 24.9 C
therefore
From the formula for sensible heat, ΔH = m×c×ΔT
we have, where
H = senced heat,
m = mass,
ΔT = temperature change
110 × 0.20 × (82.4 - 24.9) = mw × 4.186 × (24.9 - 22.3)
1265 J = mw ×10.8836 or mw = 116.23 g
Therefpre the mass of water is 116.23 g
To convert from atoms of argon to moles of argon, you need to divide by Avogadro's constant.
3.01*10^23 atoms *(1 mole/6.022*10^23 atoms) = 0.500 moles Ar
0.500 moles of Argon is equal to 3.01*10^23 atoms of Argon.