1. Ge
2. Fe
3. Zn
Remember, electronegativity decreases down a group (vertically) and increases across a period (horizontally) on the periodic table. :)
The atomic mass of a carbon isotope that has 6 protons and 7 neutrons is<u> </u><u>13</u>
Explanation:
Remember that whilst the atomic number represents the number of protons in an atom, the mass number represents the summation of protons and neutrons particles in the atomic nuclei. Therefore, in this case, the carbon will have a mass number of;
6 + 7 = 13
Isotopes of an element usually have the same atomic number but different mass numbers -because they have slightly different numbers of neutrons. An example is isotopes of Carbon; C-14 and C-12
Answer: The standard free energy change for a reaction in an electrolytic cell is always positive.
Explanation:
Electrolytic cells use electric currents to drive a non-spontaneous reaction forward.
Relation of standard free energy change and emf of cell

where,
= standard free energy change
n= no of electrons gained or lost
F= faraday's constant
= standard emf
= standard emf = -ve , for non spontaneous reaction
Thus 
Thus standard free energy change for a reaction in an electrolytic cell is always positive.
Answer:
a. 63.2%
b. 11.7%
c. 73.3%
d. 0.995%
e. 55.5%
Explanation:
An ionic compound is a compound that is formed by ions, so one of the elements must donate electrons (which is the cation, the positive ion), and the other will receive these electrons (which is the anion, the negative ion).
The power of an element has to attract the electrons is called electronegativity, and so, as higher is the difference of electronegative of the elements, it is more probable that one of them will "still" the electrons and will form an ionic compound. The percent of this ionic character can be found by the Pauling's equation:
*100%
Where
is the electronegativity difference of the elements. Thus, consulting an electronegativity table:
a.
= 1.5
= 3.5
*100%
%IC = 63.2%
b.
= 1.6
= 2.1
*100%
%IC = 11.7%
c.
= 0.7
= 3.0
*100%
%IC = 73.3%
d.
= 1.7
= 1.9
*100%
%IC = 0.995 %
e.
= 1.2
= 3.0
*100%
%IC = 55.5%