Answer:
C. Solid in liquid
Explanation:
Seawater is an example of a solid in liquid solution.
Sea water is made up of:
- water
- mineral salts
- dissolved gases
A liquid solution is always made up of a solute being dispersed within the solvent medium.
The solvent is the liquid or fluid medium.
Such solutions are homogeneous because the solute particles are distributed evenly or uniformly in the solvent.
The solute is usually present in smaller amount compared to the solvent.
Answer:
[H₂] = 13 M
[N₂] = 12 M
Explanation:
Let´s consider the following reaction at equilibrium.
3 H₂(g) + N₂(g) ⇄ 2 NH₃(g)
To find out the initial concentrations we will use an ICE chart. We recognize 3 stages: Initial, Change and Equilibrium and complete each row with the concentration or change in concentration. We will use letters for the unknown data.
3 H₂(g) + N₂(g) ⇄ 2 NH₃(g)
I a b 0
C -3x -x +2x
E a - 3x b - x 2x
We know that,
[NH₃] = 2x = 5.1 M ⇒ x = 2.6 M
Then,
[H₂] = 5.6 M = a - 3x ⇒ a = 13 M
[N₂] = 9.3 M = b - x ⇒ b = 12 M
It’s the elements that weigh the most are created when the events!
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Answer:
2445 L
Explanation:
Given:
Pressure = 1.60 atm
Temperature = 298 K
Volume = ?
n = 160 mol
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 08206 L.atm/K.mol
Applying the equation as:
1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K
<u>⇒V = 2445.39 L</u>
Answer to four significant digits, Volume = 2445 L
multiply by (6.02 times 10^23 atoms)/(1mole, cancel out atoms)
