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Umnica [9.8K]
3 years ago
5

Compare and contrast the Bohr model of the atom with the modern model of the atom. What observations does the modern model expla

in that the Bohr model did not?
Chemistry
2 answers:
GrogVix [38]3 years ago
4 0
The electron cloud model uses the basic idea of Bohr's model, representing the atom as if it were cut in half. The difference is that Bohr's model showed electrons in "shells" which modeled that they moved only in a distinct orbit around the nucleus. The modern model has layers of electrons, but models the concept that they form a cloud where their exact position is impossible to known (considering is changes). The modern model explains that electrons are not at a fixed distance from the nucleus, but the Bohr model does not represent this understanding, instead, it displays a concept that the electrons are at fixed levels of orbit.
Gwar [14]3 years ago
3 0

Answer:

According to modern model of atom that is the electron cloud atom, the electrons are found in orbitals. Orbitals are the region where there is probability to find an electron in an atom. According to Bohr's model, electrons revolve around the nucleus in fixed energy shells.

Electron cloud model explains that the position of electron cannot be found exactly. It can be found in a region. The repeating nature of chemical properties of atoms in periodic table can be explained by both the models.

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A 0.4322 g sample of a potassium hydroxide – lithium hydroxide mixture requires 27.10 mL of 0.3565 M HCl for its titration to th
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The mass percent lithium hydroxide in the mixture with potassium hydroxide, calculated from the equivalence point in the titration of HCl with the mixture, is 19.0%.  

The mass percent of lithium hydroxide can be calculated with the following equation:  

\% = \frac{m_{LiOH}}{m_{t}} \times 100    (1)

Where:

m_{t} = m_{KOH} + m_{LiOH} = 0.4322 g   (2)  

We need to find the mass of LiOH.

From the titration, we can find the number of moles of the mixture since the number of moles of the acid is equal to the number of moles of the bases at the equivalence point.    

\eta_{HCl} = \eta_{LiOH} + \eta_{KOH}

0.0271 L*0.3565 \frac{mol}{L} = \eta_{LiOH} + \eta_{KOH}

\eta_{LiOH} + \eta_{KOH} = 9.66 \cdot 10^{-3} \:mol

Since mol = m/M, where M: is the molar mass and m is the mass, we have:

\frac{m_{LiOH}}{M_{LiOH}} + \frac{m_{KOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    (3)                                        

Solving equation (2) for m_{KOH} and entering into equation (3), we can find the mass of LiOH:  

\frac{m_{LiOH}}{M_{LiOH}} + \frac{0.4322 - m_{LiOH}}{M_{KOH}} = 9.66 \cdot 10^{-3} \:mol    

\frac{m_{LiOH}}{23.95 g/mol} + \frac{0.4322 g - m_{LiOH}}{56.1056 g/mol} = 9.66 \cdot 10^{-3} \:mol              

Solving for m_{LiOH}, we have:

m_{LiOH} = 0.082 g

Hence, the percent lithium hydroxide is (eq 1):

\% = \frac{0.082 g}{0.4322 g} \times 100 = 19.0 \%  

Therefore, the mass percent lithium hydroxide in the mixture is 19.0%.

Learn more about mass percent here:

  • brainly.com/question/6992535?referrer=searchResults
  • brainly.com/question/5840377?referrer=searchResults

I hope it helps you!                        

5 0
2 years ago
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