Question

There are 3.01 x 1023 atoms of gold, 1 mole of platinum, and 3.01 moles of silver. Which contains more atoms?

Answer 1

Answer : The 3.01 moles of silver contains more number of atoms.

Explanation :

As we know that, 1 mole of substance contains $6.022\times 10^{23}$ number of atoms.

(a) The total number of atoms present in gold = $3.01\times 10^{23}$

(b) The total number of atoms present in platinum = $6.022\times 10^{23}$

(c) As, 1 mole of silver contains $6.022\times 10^{23}$ number of silver atoms.

So, 3.01 mole of silver contains $3.01mole\times (6.022\times 10^{23})=18.13\times 10^{23}$ number of silver atoms.

The total number of atoms present in silver = $18.13\times 10^{23}$

Hence, from the above we conclude that, 3.01 moles of silver contains more number of atoms.

Answer 2

We are asked in this problem to determine which of the three elements with corresponding number of moles contains the most number of atoms. To answer this, we convert the number of moles to number of atoms by multiplying Avogadro's number (6.022 x 10^23) to them. For gold, there are 3.01 x 1023 atoms; for platinum, there are 6.022 x 10^23 atoms and for silver, there are 1.81x10^24 atoms. The answer is silver.