Using the periodic table, find the neutral atom that has the same electron configuration as 1s²2s22p.

Blank moles of carbon dioxide are required to make 7.2 moles of glucose. A plant using 618 grams of carbon dioxide and plenty of

Virty [35]

Answer:

43.2 moles of carbon dioxide are required and 421g of glucose could be produced

Explanation:

Based on the reaction:

6CO2 + 6H2O → C6H12O6 + 6O2

1 mole of glucose, C6H12O6, requires 6 moles of carbon dioxide. 7.2moles of glucose requires:

7.2mol C6H12O6 * (6mol CO2 / 1mol C6H12O6) =

<h3>43.2 moles of carbon dioxide are required</h3><h3 />

618g of CO2 -Molar mass: 44.01g/mol- are:

618g * (1mol / 44.01g) = 14.04moles CO2

Moles C6H12O6:

14.04moles CO2 * (1mol C6H12O6 / 6mol CO2) = 2.34moles C6H12O6

Mass glucose -Molar mass: 180.156g/mol-

2.34moles C6H12O6 * (180.156g / mol) =

<h3>421g of glucose could be produced</h3>

7 0

3 years ago

The enthalpy change for the reaction of titanium metal with gaseous iodine is given by the following thermochemical equation: 2

julia-pushkina [17]

Answer : The enthalpy change for the reaction is, 419.5 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

The given chemical reaction is,

$2Ti(s)+3I_2(g)\rightarrow 2TiI_3(s)$ $\Delta H=-839kJ$

Now we have to determine the enthalpy change for the reaction below:

$TiI_3(s)\rightarrow Ti(s)+\frac{3}{2}I_2(g)$ $\Delta H'=?$

By reversing and then dividing the reaction by 2, we get the enthalpy change for the reaction.

The expression will be:

$\Delta H'=-\frac{(\Delta H)}{2}$

$\Delta H'=-\frac{(-839kJ)}{2}$

$\Delta H'=419.5kJ$

Therefore, the enthalpy change for the reaction is, 419.5 kJ

3 0

3 years ago

In which part of a plant cell does photosynthesis occur?

IrinaVladis [17]

Answer:

<h2>leaves,</h2>

Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)

6 0

3 years ago

Read 2 more answers

At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l

Leona [35]

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 3 atm

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 1.40 L

$V_2$ = final volume of gas = 0.950 L

$T_1$ = initial temperature of gas = $35^oC=273+35=308K$

$T_2$ = final temperature of gas = $0^oC=273+0=273K$

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}$

$P_2=3.918atm$

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

4 0

3 years ago

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Give an example of a mutation and explain how it could affect an organism?<br> Your answer

ella [17]

Answer:

A mutation is a heritable change in the genetic material of an individual. The change can be large or small. Large changes involve the loss, addition, duplication, or rearrangement of whole chromosomes or chromosome segments. Mutations can affect an organism by changing its physical characteristics (or phenotype) or it can impact the way DNA codes the genetic information (genotype). When mutations occur they can cause termination (death) of an organism or they can be partially lethal.

Explanation:

8 0

3 years ago