Answer:
![\boxed {\boxed {\sf 117.6 \ L \ He}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20117.6%20%5C%20L%20%5C%20He%7D%7D)
Explanation:
Regardless of the type of gas, 1 mole at standard temperature and pressure (STP) occupies a volume of 22.4 liters. In this case the gas is helium (He).
We can set up a ratio.
![\frac { 22.4 \ L \ He}{ 1 \ mol \ He}](https://tex.z-dn.net/?f=%5Cfrac%20%7B%2022.4%20%5C%20L%20%5C%20He%7D%7B%201%20%5C%20mol%20%5C%20He%7D)
Multiply by the given number of moles.
![5.25 \ mol \ He *\frac { 22.4 \ L \ He}{ 1 \ mol \ He}](https://tex.z-dn.net/?f=5.25%20%5C%20mol%20%5C%20He%20%2A%5Cfrac%20%7B%2022.4%20%5C%20L%20%5C%20He%7D%7B%201%20%5C%20mol%20%5C%20He%7D)
The moles of helium will cancel.
![5.25 *\frac { 22.4 \ L \ He}{ 1 }](https://tex.z-dn.net/?f=5.25%20%2A%5Cfrac%20%7B%2022.4%20%5C%20L%20%5C%20He%7D%7B%201%20%7D)
![5.25 * { 22.4 \ L \ He}](https://tex.z-dn.net/?f=5.25%20%2A%20%7B%2022.4%20%5C%20L%20%5C%20He%7D)
Multiply.
![117.6 \ L \ He](https://tex.z-dn.net/?f=117.6%20%5C%20L%20%5C%20He)
5.25 moles of helium gas at STP is 117.6 liters of helium.
Answer:
yes
Explanation:
when you are not looking directly at it it won't affect you in any way
Answer: 2.51 moles of oxygen is consumed
Explanation:
Exothermic reaction : It is a type of chemical reaction where the energy is released into the surrounding. In the exothermic reaction, the energy of reactant are more than the energy of product.
In exothermic reaction, the change in enthalpy is, negative
The balanced chemical reaction is:
![\Delta H=-285.8kJ](https://tex.z-dn.net/?f=%5CDelta%20H%3D-285.8kJ)
According to stoichiometry:
When 1 mole of oxygen is consumed , energy released = 285.8 kJ
285.8 kJ of energy is evolved when oxygen consumed = 1 mol
Thus whn 717.4 kJ of energy is evolved when oxygen consumed =
moles
2.51 moles of oxygen is consumed
Answer:
7.5 × 10¹⁵ Hz
Explanation:
Given data
- Wavelength of the radio waves (λ): 40 nm = 40 × 10⁻⁹ m = 4.0 × 10⁻⁸ m
- Frequency of the radio waves (ν): ?
- Speed of light (c): 3.00 × 10⁸ m/s
We can determine the frequency of the radio waves using the following expression.
c = λ × ν
ν = c/λ
ν = (3.00 × 10⁸ m/s)/4.0 × 10⁻⁸ m
ν = 7.5 × 10¹⁵ s⁻¹ = 7.5 × 10¹⁵ Hz