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mrs_skeptik [129]
3 years ago
5

A mother pulls her two children on a sled through the snow along a flat street. How much work is done if she pulls her children

100 feet with a constant force of 40 pounds at an angle of 28°?
Chemistry
1 answer:
dimaraw [331]3 years ago
4 0
W=F.s
W=40cos28 x 100
Press the calculator yourself
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3 years ago
What type of energy is the sun of an objects potential and kinetic energy
Ulleksa [173]

All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays. Radiation is one way to transfer heat.

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4 years ago
Where is lithium used in the body?
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Answer:

Lithium is a naturally occurring alkali metal, which living organisms ingest from dietary sources and which is also present in trace amounts in the human body. In much higher concentrations, lithium is effective as a medication for mania and mood swings including manic depressive disorders

7 0
4 years ago
Read 2 more answers
Can Sodium be used to distinguish between cyclobutanol and butanoic acid
Anvisha [2.4K]

Answer:

\boxed{\text{No}}

Explanation:

Na reacts with all OH groups to produce hydrogen.

The reaction with cyclobutanol is shown below.  

The reaction with butanoic acid is

\rm CH_{3}CH_{2}CH_{2}COOH\xrightarrow{\text{Na}} CH_{3}CH_{2}CH_{2}COO^{-} + H_{2}

Both compounds release bubbles of hydrogen, so you can't use sodium to distinguish between them.

5 0
3 years ago
Se mezclan 20 gramos de agua (1cal/g°C) a 40 °C con 15 gramos de alcohol (0,58cal/g°C) a 30 °C. ¿Cuál ha sido la temperatura de
madreJ [45]

Answer:

T_{EQ}=37\°C

Explanation:

¡Hola!

En este caso, para los problemas de equilibrio térmico, consideramos que la energía liberada por la sustancia que inicialmente está caliente (agua), es absorbida por la sustancia que inicialmente está fría (alcohol); thus, we can write:

Q_{agua}=-Q_{alcohol}

La cual puede ser escrita en términos de masa, calor specifico y temperaturas:

m_{agua}C_{agua}(T_{EQ}-T_{agua})=-m_{alcohol}C_{alcohol}(T_{EQ}-T_{alcohol})

De este modo, al resolver para la temperature de equilibrio térmico, obtenemos la siguiente expresión:

T_{EQ}=\frac{m_{agua}C_{agua}T_{agua}+m_{alcohol}C_{alcohol}T_{alcohol}}{m_{agua}C_{agua}+m_{alcohol}C_{alcohol}}

Así, al reemplazar los valores en esta, obtenemos:

T_{EQ}=\frac{(20g)(1cal/g\°C)(40\°C)+(15g)(0.58cal/g\°C)(30\°C)}{(20g)*(1cal/g\°C)+(15g)(0.58cal/g\°C)} \\\\T_{EQ}=37\°C

¡Saludos!

3 0
3 years ago
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