Answer:
T= In(2)/___ =__ In(2)
Explanation:
the equation pices arnt on the keyboard so i put the blanks
sorry
jope it helps some. Have a good day ir night! :)
Answer
Force between two charged bodies q₁ and q₂ is given by the formula below.
F = Kq₁q₂/r²
Where k = constant
r = distance between them
F = (9.0 E9 × 1.0 E-6 × 1.0 E-6)/0.30²
= 9.0E-3/0.30²
= 9.0E-3/0.09
= 0.1 N
Answer:
yes
Explanation:
please Mark my answer in brainlist and follow me
Answer:
v = (78.0 i ^ - 70.27 j ^) m/s, v = 105 m / s
, θ = 318º
Explanation:
We have a projectile launch problem, let's start by calculating the time it takes to get through the canyon
y = t - ½ gt2
As the motorcyclist comes out horizontally, the speed he has is the horizontal speed (vox) and the initial vertical speed is zero (I go = 0)
y = 0 - ½ g t2
t = √ 2y / g
t = √ (2 252 /9.8)
t = 7.17 s
Let's calculate the vertical speed for this time
= - gt
= 0 - gt
= - 9.8 7.17
= - 70.27 m / s
We can give the result in two ways
First:
v = (78.0 i ^ - 70.27 j ^) m / s
Second:
using the Pythagorean theorem and trigonometry
v² = vₓ² + ²
v = √ [(78.0)² + (-70.42)²] = √ (11042.98)
v = 105 m / s
tan θ₁ = y / vₓ
tan θ₁ = -70.42 / 78.0
θ₁ = 42º
If we measure this angle from the positive direction of the x-axis counterclockwise
θ = 360 - θ₁
θ = 360 - 42
θ = 318º