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Rama09 [41]
2 years ago
7

Good morning! Can someone please answer this, ill give you brainliest and you will earn 50 points.

Physics
2 answers:
olga55 [171]2 years ago
6 0

Constructive force ➡️ <em>Process</em><em> </em><em>where</em><em> </em><em>crust</em><em> </em><em>is</em><em> </em><em>formed</em>

Destructive force ➡️ <em>Process</em><em> </em><em>where</em><em> </em><em>crust</em><em> </em><em>is</em><em> </em><em>destroyed</em>

Weathering ➡️ <em>Break</em><em> </em><em>down</em><em> </em><em>of</em><em> </em><em>rock</em><em> </em><em>materials</em>

Erosion ➡️ <em>Movement</em><em> </em><em>of</em><em> </em><em>broken</em><em> </em><em>down</em><em> </em><em>rock</em><em> </em><em>material</em>

Tectonic uplift ➡️ <em>Upward</em><em> </em><em>movement</em><em> </em><em>of</em><em> </em><em>crust</em>

iren2701 [21]2 years ago
5 0
  • Constructive force:-process where crust is formed
  • Destructive force:- process where the crust is destroyed
  • weathering:-Movement of broken down rock material.
  • Erosion:-Break down of rock materials
  • Techtonic uplift :-Upward movement of crust
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A car is traveling at 75 m/s. 50 seconds later it is traveling at 25 m/s. What is the car’s acceleration?
scoray [572]

Answer:

a = -1 m/s^2

Explanation:

Vi = 75 m/s

Vf = 25 m/s

t = 50 s

Plug those values into the following equation:

Vf = Vi + at

25 = 75 + 50a

---> a = -1 m/s^2

5 0
3 years ago
The kinetic energy of the molecules inside the balloon _______ which
11111nata11111 [884]

Answer:

Increase,.faster

Explanation:

The kinetic energy of the molecules inside the balloon

increases

which means they are moving

faster

I hope this helps you :)

6 0
3 years ago
If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st
liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the  the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0
2 years ago
Suppose a large power plant generates electricity at 12.0 kV. Its old transformer once converted this voltage to 315 kV. The sec
SpyIntel [72]

Answer:

  • 2.32
  • 0.43

Explanation:

12.0 kv primary voltage

315 kv secondary voltage ( converted voltage ) V1 or Vo

v2 (Vn)= 730 kv new secondary voltage

a) Ratio of turns in 730 kv to turns in 315 kv

\frac{Vn}{Vo} = \frac{Nn}{No} = \frac{730}{315}  therefore the ratio of turns = 2.317 ≈ 2.32

B) ratio of the new current output to the old current output for the same power input to the transformer

since the power input is the same

\frac{In}{Io} = \frac{\frac{Vp}{Vn} }{\frac{Vp}{Vo} }     equation 1

Vp = primary voltage, Vo = old secondary voltage, Vn = new secondary voltage, In = new secondary current, Io = old secondary current

therefore equation 1 becomes

\frac{In}{Io}  = \frac{Vo}{Vn} =  315 / 730 = 0.43

7 0
3 years ago
Resistance of a conductor is directly proportional to length.<br> a. True<br> b. False
PtichkaEL [24]

If everything else is held constant ... the substance from which
the conductor is formed, its cross-sectional area, its temperature
everywhere along its length ... then yes, its resistance will be
directly proportional to its length.

4 0
3 years ago
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