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melisa1 [442]
3 years ago
15

The earth revolves around the sun in its orbit as shown in the figure. Is there any difference in the amount of gravitational fo

rce of the sun towards the earth when the earth moves from a point A to point B on its orbit? Explain.​

Physics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

No.

Explanation:

There is no change in gravitational force based on the sizes remaining the same. If there was a change in gravitational force the orbits of all planets would change.

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LenaWriter [7]
The correct answer to this question is 15
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What is the correct chemical name for C7H8?
Nesterboy [21]

Answer:

Cycloheptatriene

Explanation:

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3 years ago
Read 2 more answers
Let’s say I am in a bumper car and have a velocity of 14 m/s, driving in the positive x-direction. I and my bumped car have a ma
AlekseyPX

Answer:

160 kg

12 m/s

Explanation:

m_1 = Mass of first car = 120 kg

m_2 = Mass of second car

u_1 = Initial Velocity of first car = 14 m/s

u_2 = Initial Velocity of second car = 0 m/s

v_1 = Final Velocity of first car = -2 m/s

v_2 = Final Velocity of second car

For perfectly elastic collision

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}

Applying in the next equation

v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s

m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg

Mass of second car = 160 kg

Velocity of second car = 12 m/s

5 0
3 years ago
Correct the following statement:
ankoles [38]

Answer:

It's the 3rd option

Explanation:

Wind is caused by the differences in air pressure on Earth's surface.

4 0
3 years ago
Assume a solar cell would produce a current of 500mA and 3 V. What is the power of this solar cell?
defon

Answer:

the power of the solar cell is 1.5 watts

Explanation:

Recall that power is defined as the product of the voltage (V) times the running current (I): Power = V * I.

The only thing we have to take care of before actually performing the operation, is to convert milliamps into Amps, so our answer comes directly in the appropriate units (Watts). 500 mAmps can be written as 0.5 Amps, then, the product becomes:

Power = V * I = 3 V * 0.5 Amps = 1.5 watts

8 0
3 years ago
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