Answer:
Length of the ramp, l = 31.22 feet
Explanation:
It is given that,
A doorway is 2.45 ft above the ground, AB = 2.45 ft
Angle between the ground and the ramp is,
Applying trigonometry,
AC = 31.22 ft
So, the length of the ramp is 31.22 feet. Hence, this is the required solution.
Answer:
(a) 51428.59 J/C
(b) 25714.29 J/C
(c) 0 J/C
Explanation:
Parameters given:
Q1 = 2 * 10^-6 C
Q2 = 2 * 10^-6 C
Q3 = 2 * 10^-6 C
Q4 = 2 * 10^-6 C
=> Q1 = Q2 = Q3 = Q4 = Q
Side of the square = 2m
The center of the square is the midpoint of the diagonals, i.e. Using Pythagoras theorem:
BD² = 2² + 2²
BD² = 8
BD = √(8) = 2.8m
OD = 1.4m
(The attached diagram explains better)
Hence, the distance between the center and each point charge, r, is 1.4m.
Electric Potential, V = kQ/r
k = Coulombs constant
(a) If all charges are positive:
V(Total) = V1 + V2 + V3 + V4
V1 = Potential due to Q1
V2 = Potential due to Q2
V3 = Potential due to Q3
V4 =Potential due to Q4
Since Q1 = Q2 = Q3 = Q4 = Q
=> V1 = V2 = V3 = V4
=> V(Total) = 4V1
V = (4 * 9 * 10^9 * 2 * 10^-6)/1.4
V = 51428.59J/C
(b) If 3 charges are positive and 1 is negative:
Since Q1 = Q2 = Q3 = Q
and Q4 = -Q
The total potential becomes:
V(Total) = V1 + V2 + V3 - V4
Since V1, V2, V3 and V4 have the same value,
V(Total) = V1 + V2
V(Total) = 2V1
V(Total) = (2 * 9 * 10^9 * 2 * 10^-6)/1.4
V(Total) = 25174.29 J/C
(c) Two charges are positive and two are negative:
Since Q1 = Q2 = Q
and Q3 = Q4 = -Q
The total potential becomes:
V(Total) = V1 + V2 - V3 - V4
Since V1, V2, V3 and V4 have the same value,
V(Total) = 0 J/C
Answer:
The current increases when the circuit is closed.
Explanation:
As the complete question is not given, the complete question is attached herewith.
From the data the resistors are connected in parallel and the value of Battery EMF is increased thus as the resistance is decreased and the EMF of the battery is increased, thus the current will increase when the switch is closed.
