The easiest way to answer this question is just to get the answer first. The answer is A with the added comment that no chemical reaction has taken place.
Layered means that the chemicals are not soluble in one another. B is not the answer.
C is eliminated by what what was said about A.
D a solution is not a pure substance (singular) by itself. There are at least 2 chemicals together.
 
        
             
        
        
        
I can think of two possible and logical questions for the problem given. First, you can calculate for the maximum height reached by the blue ball. Second, you can compute the length of time for the two balls to be at the same height. If so, the solution are as follows:
When the object is thrown upwards or when the object is dropped from a height, the only force acting upon it is the gravitational force. Because of this, it simplifies equations of motion.
1. For the maximum height, the equation is
H = v₀²/2g
where
v₀ is the initial speed
g is the acceleration due to gravity equal to 9.81 m/s²
For the blue ball, v₀ = 21.8 m/s. Substituting the values:
H = (21.8 m/s)²/2(9.81m/s²)
H = 24.22 m
The maximum height reached by the blue ball is 24.22 m + 0.9 = 25.12 m.
2. For this, you equate the y values of both balls:
y for red ball = y for blue ball
v₀t + 0.5gt² = v₀t + 0.5gt²
(10.4 m/s)t + 0.5(9.81 m/s²)(t²) + 26.6 m = (21.8 m/s)t + 0.5(9.81 m/s²)(t²) + 0.9 m
Solving for t, 
t = 2.25 seconds
Thus, the two balls would be at the same height after 2.25 seconds.
        
             
        
        
        
Explanation:
First, we need to determine the distance traveled by the car in the first 30 minutes,  .
.
Notice that the unit measurement for speed, in this case, is km/hr. Thus, a unit conversion of from minutes into hours is required before proceeding with the calculation, as shown below
                                           
Now, it is known that the car traveled 40 km for the first 30 minutes. Hence, the remaining distance,  , in which the driver reduces the speed to 40km/hr is
 , in which the driver reduces the speed to 40km/hr is
                                               .
.
Subsequently, we would also like to know the time taken for the car to reach its destination, denoted by   .
.
                                                .
.
Finally, with all the required values at hand, the average speed of the car for the entire trip is calculated as the ratio of the change in distance over the change in time.
                                                      
Therefore, the average speed of the car is 50 km/hr.
 
        
             
        
        
        
The work done on the puck is 96 J
Explanation:
According to the work-energy theorem, the work done on the hockey puck is equal to the change in kinetic energy of the puck.
Mathematically:
 
where
 is the final kinetic energy of the puck, with
 is the final kinetic energy of the puck, with
m = 2 kg being the mass of the puck
v = 10 m/s is the final speed
 is the initial kinetic energy of the puck, with
 is the initial kinetic energy of the puck, with
u = 2 m/s being the initial speed of the puck
Substituting numbers into the equation, we find the work done by the player on the puck:
 
Learn more about work and kinetic energy:
brainly.com/question/6763771  
brainly.com/question/6443626  
brainly.com/question/6536722
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