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2 years ago

Since you've determined that the power supply is a 700W dual rail, what does that make the maximum output power?

Physics

1 answer:

inysia [295]2 years ago

6 0

700 makes the maximum output power.

<u>Explanation:</u>

In physics, power is the rate of doing work or of transferring heat, i.e. the amount of energy transferred or converted per unit time. The output power of a motor is the product of the torque that the motor generates and the angular velocity of its output shaft.

A joule is equal to one Newton-meter, which is the amount of work needed to move a 1 Newton force a distance of 1 meter. When you divide work by time, you get power, measured in units of joules per second. This is also called a Watt. 1 Watt = 1 Joule Sec. This is the formula to calculate output power.

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A parallel-plate capacitor stores charge Q. The capacitor is then disconnected from its voltage source, and the space between th

Stells [14]

Answer:

The relationship between the initial stored energy $PE_{i}$ and the stored energy after the dielectric is inserted $PE_{f}$ is:

c) $PE_{f} =0.5\ PE_{i}$

Explanation:

A parallel plate capacitor with $C_{o}$ that is connected to a voltage source $V_{o}$ holds a charge of $Q_{o} =C_{o} V_{o}$ . Then we disconnect the voltage source and keep the charge $Q_{o}$ constant . If we insert a dielectric of $\kappa=2$ between the plates while we keep the charge constant, we found that the potential decreases as:

$V=\frac{V_{o}}{\kappa}$

The capacitance is modified as:

$C=\frac{Q}{V} =\kappa\frac{Q_{o}}{V_{o}}=\kappa\ C_{o}$

The stored energy without the dielectric is

$PE_{i}=\frac{1}{2}\frac{Q_{o}^{2}}{C_{o}}=\frac{1}{2}C_{o}V_{o}^{2}$

The stored energy after the dielectric is inserted is:

$PE_{f}=\frac{1}{2}\frac{Q^{2}}{C}=\frac{1}{2}CV^{2}$

If we replace in the above equation the values of V and C we get that

$PE_{f}=\frac{1}{2}\kappa\ C_{o}(\frac{V_{o}}{\kappa})^{2}=\frac{1}{\kappa}(\frac{1}{2}C_{o}V_{o}^{2})$

$PE_{f} =\frac{PE_{i}}{\kappa}$

Finally

$PE_{f} =0.5\ PE_{i}$

5 0

3 years ago

What selective pressures favored an increase in brain size in hominid primates?

Viktor [21]

The colossal brains of people are to a great extent because of one segment the cerebral cortex. The cerebral cortex is the focal point of dialect, rationale, critical thinking, and data preparing. A high bent in these territories would be exceptionally favorable to primitive seekers.

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3 years ago

Read 2 more answers

A man in a strength competition pulls an 18-wheel truck 3.10 m in 20.5 s. There is a cable that is attached to his body that exe

larisa [96]

Answer:

114.32195122 but Round your answer to three significant figures.) is 114

Explanation:

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3 years ago

Gravitational force of attraction “F” exists between two point masses A and B when a fixed distance separates them. After mass A

DIA [1.3K]

Answer:

the new gravitational force between the two masses is $\frac{3}{2}$ of the original force (third option in the provided list)

Explanation:

Recall the expression for gravitational force : $F_g=G\,\frac{m_A*\,m_B2}{d^2}$ , where $m_A$ and $m_B$ are the point masses, d the distance between them, and G the universal gravitational constant.

I our problem, the distant between the particles stays unchanged, and we need to know what happens with the magnitude of the force as mass A is tripled, and mass B is halved.

Initial force expression: $F_i=G\,\frac{m_A\,m_B}{d^2}$

Final force expression: $F_f=G\,\frac{3*m_A\,m_B/2}{d^2}\\F_f=G\,\frac{m_A\,m_B\,*\,3/2}{d^2}\\F_f=G\,\frac{m_A\,m_B}{d^2}\,*\frac{3}{2} \\F_f=F_i\,*\frac{3}{2}$

Where we have recognized the expression for the initial force between the particles, and replaced it with $F_i$ to make the new relation obvious.

Therefore, the new gravitational force between the two masses is $\frac{3}{2}$ of the original force.

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3 years ago

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A gas bottle contains 0.650 mol of gas at 730 mm Hg pressure. If the final pressure is 1.15 atm, how many moles of gas were adde

AlekseyPX

Answer:

0.779 mol

Explanation:

Since the gas is in a bottle, the volume of the gas is constant. Assuming the temperature remains constant as well, then the gas pressure is proportional to the number of moles:

$p \propto n$