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Brut [27]
3 years ago
7

At 488 mm Hg, a sample of nitrogen gas occupies 609 mL. What volume does the gas occupy if the temperature remains constant and

the pressure increases to 757.8 mm Hg?
Select one:
a. 392
b. 607
c. 0.00529
d. 1000
Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

a. 392

Explanation:

According to Boyles law, the pressure of a fixed mass of a gas at constant temperature is inversely proportional to the volume.

P1V1=P2V2

P1=488mm Hg

P2=757.8mm Hg

V1=609 mL

Therefore we use the values above in the formula and get:

488 mm Hg×609 mL=757.8 mm Hg×V2

V2=(488mmHg×609 mL)/757.8 mm Hg

=392.177 mL

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Answer:

carbon dioxide and water

Explanation:

Example: Combustion of Methane (CH₄(g))

CH₄(g) + 2O₂(g) => CO₂(g) + 2H₂O(g)**

____________________

Note: The combustion of any hydrocarbon produces CO₂ & H₂O. That is,

Ethane (C₂H₆) + O₂ => CO₂(g) + H₂O(g)

Propane (C₃H₈) + O₂ => CO₂(g) + H₂O(g)

Butane (C₄H₁₀) + O₂ => CO₂(g) + H₂O(g)

The issue remaining is to balance the reaction equation. For these type equation balance Carbon 1st, then Hydrogen and finish with Oxygen. Balancing in this order leaves Oxygen which can be balanced using fractions. If problem requires lowest whole number ratios of elements, simply multiply entire equation by 2 to get standard equation*

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*Standard Equation is defined as the smallest whole number ratios of elements. The 'standard equation' is significant in that it is assumed to be at STP conditions; i.e., 0⁰C (=273K) & 1.0 Atmosphere pressure.

  • Ethane (C₂H₆) + 7/2O₂(g) => 2CO₂(g) + 3H₂O(g)

    => 2C₂H₆ + 7O₂(g) => 4CO₂(g) + 6H₂O(g)  <= Standard Form of Rxn

  • Propane (C₃H₈) + 5O₂(g) => 3CO₂(g) + 4H₂O(g) <= Standard Form of Rxn (no need to balance with the '2' multiple)
  • Butane (C₄H₁₀) + 13/2O₂ => 4CO₂(g) + 5H₂O(g)

    => 2C₃H₈ + 13O₂(g) => 4CO₂(g) + 5H₂O(g) <= Standard Form of Rxn

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**Also, note that water, H₂O(g), is listed as a gas. In some cases it will be listed as a liquid, H₂O(l).

3 0
4 years ago
Read 2 more answers
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vampirchik [111]

Answer:

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Explanation:

<u>1) Convert absolute zero to celsius:</u>

  • 0 K = - 273.15°C ( this is per definition of the scale)

<u>2) Convert - 273.15°C to Fahrenheit:</u>

  • T (°F) = T (°C) × 1.8 + 32 (this is the conversion equation=

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8 0
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Verizon [17]
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7 0
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Vlad1618 [11]

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Explanation:

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This is best illustrated by the option-D in the figure and therefore is the correct answer.

7 0
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Answer:

r = k [ B ]

Explanation:

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⇒ r = k [ A ]/2 = k [ B ]

3 0
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