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vichka [17]
3 years ago
12

Describe two uses of surfactants. At least one must be something that was not described in the passage. For each example, explai

n how the effects of the surfactant make it useful.
Chemistry
2 answers:
notka56 [123]3 years ago
8 0
There are several types of surfactants, to name two: alkylbenzene sulfonates  or detergents; and lauryl sulfate or foaming agents. 

Alkylbenzene sulfonates are commonly used in the production of detergent soaps, these help clean the dirt from cloths and other materials, it also produces foam. 

Lauryl sulfate or foaming agents are commonly used in the production of dishwashing liquid or handwashing soap. 
rusak2 [61]3 years ago
8 0

Alkylbenzene sulfonates are commonly used in the production of detergent soaps, these help clean the dirt from cloths and other materials, it also produces foam. Lauryl sulfate or foaming agents are commonly used in the production of dishwashing liquid or handwashing soap. 

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Chemistry Question! Please help ASAP!! <br> Would really appreciate!
Ivan
A mixture of Cu2 and CuO of mass 8.828g is reduced to copper metal with hydrogen:
Cu2O + H2 --> 2Cu + H2O
CuO + H2 --> Cu + H2O

If the mass of pure copper isolated was 7.214g, determine the percent by mass of CuO in the original sample

Let x = grams of CuO in the original sample.
y = grams of Cu2O in the original sample.

Eq. #1 x + y = 8.828 grams

Molar mass of CuO = 63.5 + 16 = 79.5 grams
Moles of CuO = x ÷ 79.5

Molar mass of Cu2O = 63.546 + 32 = 95.5 grams
Moles of Cu2O = y ÷ 95.5

According to the 2nd balanced equation, CuO + H2 --> Cu + H2O ,
1 mole of CuO produces 1 mole of Cu.
So, x ÷ 79.5 moles of CuO will produce x ÷ 79.5 moles of Cu


According to the 1st balanced equation, Cu2O + H2 --> 2Cu + H2O,
1 mole of Cu2O produces 2 moles of Cu
So, (y ÷ 95.5) moles of Cu2O will produce 2 * (y ÷ 95.5) moles of Cu

Since, the mass of pure copper isolated was 7.214 grams
Moles of Cu = (7.214 ÷ 63.5)

Moles of Cu from Cu2O + moles of Cu from CuO = total moles of Cu!!

2 * (y ÷ 95.5) + (x ÷ 79.5) = (7.214 ÷ 63.5)
Multiply by both sides by 95.5 * 79.5 * 63.5 to get rid of denominators

(2 * 79.5 * 63.5) y + (95.5 * 63.5) x = (7.214 * 95.5 * 79.5)

10,096.5 y + 6,064.25 x = 36,418.0755
Divide both sides by 6,064.25
x + 1.665 y = 6

Eq.#2 x = 6 – 1.665 y
Eq. #1 x + y = 8.828
x = 8.828 – y

8.828 – y = 6 – 1.665 y
0.665 y = 2.828
y = 4.25 grams of Cu2O
x = 8.828 – 4.25 = 4.58 grams of CuO

% CuO = (4.58 ÷ 8.828) * 100 = 51.88% CuO
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The high level of pollution in earth's is a planet problem
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Answer:

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Numerator and denominator are Equal to one another? <br> I don’t get the concept
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It's like saying that if 1 meter is equal to 100 cm,

\frac{100cm}{1m}

or

\frac{1m}{100cm}

You can base the answers from the chart

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Hey student made a model of a river in a sandbox a pile of sand represents soil and bits of rocks in the riverbed water pouring
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Answer:

The model is missing plants, fish and other details found in a real river

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Explanation:

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It is determined by its ELECTRIC CONFIGURATION.
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