S = (-5,0)
T = (2,1)
Step-by-step explanation:
Step 1 :
Given
Q = (3,6) and R = (-4,5). P = (-1,3)
Let S be (a,b) and T be (c,d)
The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.
Step 2 :
P is the midpoint of QS
So we have (3+a) ÷ 2 = -1 and (6 + b) ÷ 2 = 3
=> 3 + a = -2 and 6 + b = 6
=> a = -5 and b =0
So S should be (-5,0)
Step 3 :
P is the midpoint of RT
So we have (-4+c) ÷ 2 = -1 and (5 + d) ÷ 2 = 3
=> -4+ c = -2 and 5 + d = 6
=> c = 2 and d =1
So T should be (2,1)
Step 4 :
Answer :
S = (-5,0)
T = (2,1)
1/4 (8 + 6z + 12)
------------------------------------------------------------
Combine like terms :
------------------------------------------------------------
1/4 (6z + 20)
------------------------------------------------------------
Apply distributive property :
------------------------------------------------------------
1/4(6z) + 1/4(20)
3/2z + 5
------------------------------------------------------------
Answer: 3/2z + 5
------------------------------------------------------------
Answer:
132
Step-by-step explanation:
Circumference = 360 degrees
<span>Circumference = 2π radians (comes from 2*pi*radius) </span>
<span>Therefore </span>
<span>360 deg. = 2*π radians </span>
<span>180 deg. = π radians </span>
<span>1 deg. = (π/180) radians </span>
<span>75 deg. = 75(π/180) radians </span>
<span>75 deg. = 75π / 180 radians </span>
<span>don't bother to try and simplify π (it is an irrational number) </span>
<span>however you can simplify 75/180 </span>
<span>both are divisible by 5 </span>
<span>75π/180 = 15π/36 </span>
<span>both are divisible by 3 </span>
<span>75 deg. = 5π/12 radians </span>
<span>We normally don't bother to go further, unless you actually need it as a decimal fraction (in which case, you will have an approximation) </span>
<span>75 deg. ≈ 1.308997 radians</span>
