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ankoles [38]
3 years ago
8

Thallium consists of 29.5%TI-203 and 70.5%TI-205. What is the relative atomic mass of thallium?

Physics
1 answer:
Kazeer [188]3 years ago
7 0
Since you are referring to the TI-203 and TI-205, you need to know the actual masses of these two isotopes. TI-203 has 202.9723 amu  and TI-205 has 204.9744 amu. Since you are concluding that this Thallium have 29.5% (Ti-203) and 70.5% (Ti-205), you need to multiply the percentage to the actual masses of the isotopes. With that, you should be able to get 204.3833 amu
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A 14n force is applied for 0.33 seconds, calculate the impulse
Shalnov [3]

Answer:

4.62 N-s

Explanation:

recall that the formula for impulse is given by

Impulse = Force x change in time

in our case, we are given

Force = 14 N

change in time = 0.33s

Simply substituting the above into the equation for impulse, we get

Impulse = Force x change in time

Impulse = 14 x 0.33

= 4.62 N-s

5 0
3 years ago
Two metallic rods A and B of different materials have same length. The linear expansivity of A is 12×10–6 oC–1and cubical expans
uysha [10]

Answer:

The length of rod A will be <u>greater than </u>the length of rod B

Explanation:

We, know that the formula for final length in linear thermal expansion of a rod is:

L' = L(1 + ∝ΔT)

where,

L' = Final Length

L = Initial Length

∝ = Co-efficient of linear expansion

ΔT = Change in temperature

Since, the rods here have same original length and the temperature difference is same as well. Therefore, the final length will only depend upon the coefficient of linear expansion.

For Rod A:

∝₁ = 12 x 10⁻⁶ °C⁻¹

For Rod B:

∝₂ = β₂/3

where,

β₂ = Coefficient of volumetric expansion for rod B = 24 x 10⁻⁶ °C⁻¹

Therefore,

∝₂ = 24 x 10⁻⁶ °C⁻¹/3

∝₂ = 8 x 10⁻⁶ °C⁻¹

Since,

∝₁ > ∝₂

Therefore,

L₁ > L₂

So, the length of rod A will be <u>greater than </u>the length of rod B

6 0
3 years ago
A bus driver drove her bus for 5 miles. She drove that distance in a total of 30 minutes. What was the truck driver's average sp
nexus9112 [7]

Answer:

\mathrm{b.\:}0.17\:\mathrm{miles/minute}

Explanation:

Average speed is given by S=\frac{d}{t} where d is total distance and t is time.

Plugging in given values, we get:

S=\frac{5\:\mathrm{miles}}{30\:\mathrm{minutes}}=\fbox{$\mathrm{b.\:}0.17\:\mathrm{miles/minute}$}.

4 0
3 years ago
Sophie throws a tennis ball down from a height of 1.5 m at an angle of 450 with respect to vertical. She drops another tennis ba
Katena32 [7]

Given that,

Height =1.5 m

Angle = 45°

We need to find the greater speed of the ball

Using conservation of energy

P.E_{i}+K.E_{f}=P.E_{f}+K.E_{f}

mgh+\dfrac{1}{2}mv_{i}^2=mgh+\dfrac{1}{2}mv_{f}^2

Here, initial velocity and final potential energy is zero.

mgh=\dfrac{1}{2}mv_{f}^2

Put the value into the formula

9.8\times1.5=\dfrac{1}{2}v_{f}^2

v_{f}^2=2\times9.8\times1.5

v_{f}=\sqrt{2\times9.8\times1.5}

v_{f}=5.42\ m/s

Hence, the greater speed of the ball is 5.42 m/s.

5 0
3 years ago
If you speed up from the rest to 12m/s in 3 seconds, what is your acceleration?
azamat

I believe that your acceleration would be 4 m/s

7 0
4 years ago
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