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Alik [6]
3 years ago
15

A soccer player carries the ball for a distance of 40.0 m in the direction 42.0° west of south. find the westward component of t

he ball's displacement.

Physics
1 answer:
Maksim231197 [3]3 years ago
3 0

Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.

We can see from the figure that to solve for the value of the horizontal component, we have to make use of the sin function. That is:

sin θ = side opposite to the angle / hypotenuse of the triangle

sin 42 = x / 40 m

x = (40 m) sin 42

x = 26.77 m

 

Therefore the ball has a westward displacement of about 26.77 m

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Answer:

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Explanation:

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P_{2}=\dfrac{r_{2}^2}{r_{1}^{2}}\timesP_{1}

Put the value into the formula

P_{2}=\dfrac{18^2}{38^2}\times110\times10^{-3}

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Akimi4 [234]

Answer:

a. \mathbf{F_{f_2} = 2 F_{f1}}, \mathbf { since \ the \ force \ o f \ friction  \ is \ represented  \ as  \ the \  slope \ for \ each  \ of  \ the \ two  \ curves.}

Explanation:

From the information given;

Using the work-energy theorem

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Since K_1 = K_2 and r_1 = 4, and r_2 = 2 (from the missing diagram which is attached below)

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1 = \dfrac{F_{f1}}{F_{f2}} (\dfrac{4 \ m}{2 \ m})

\mathbf{F_{f_2} = 2 F_{f1}}

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