Actually what the problem meant about the westward component of the ball’s displacement is the horizontal component of the displacement. To help us better understand the problem, I attached a figure of the situation.
We can see from the figure that to solve for the value of the horizontal component, we have to make use of the sin function. That is:
sin θ = side opposite to the angle / hypotenuse of the triangle
sin 42 = x / 40 m
x = (40 m) sin 42
x = 26.77 m
Therefore the ball has a westward displacement of about 26.77 m
Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where =Angular frequency
A=Amplitude
Using the formula
Hence, the amplitude of oscillation=A=0.199
Answer:
Explanation:
Newton's 2nd Law relates the net force <em>F</em> on an object of mass <em>m </em>with the acceleration <em>a</em> it experiments by <em>F=ma.</em> In our case the net force is the friction force, since it's the only one the skier is experimenting horizontally and the vertical ones cancel out since he's not moving in that direction. Our acceleration then will be:
Also, acceleration is defined by the change of velocity in a given time t, so we have:
Since we want the change in velocity, <em>mixing both equations</em> we conclude that:
Which for our values means: