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Vlada [557]
3 years ago
6

A person is riding on a Ferris wheel of radius R. He starts at the lowest point of the wheel. When the wheel makes one complete

revolution, is the net work done by the gravitational force positive, zero or negative? Do you need to know how the speed of the person changed before you can answer the question?
Physics
1 answer:
Wittaler [7]3 years ago
4 0

Answering the two questions in reverse order:

-- No. I don't need to know how the speed of the person changed before I can answer the question.  I can answer it now.

-- The NET work done by the gravitational force is<em> zero</em>.

-- As the person and his girl-friend go up the first half of the wheel, the motor does positive work and gravity does negative work.

-- After they pass the peak at the top and come down the second half of the wheel, the motor does negative work and gravity does positive work, even though the couple may be interested in other things during that time.

-- The total work done by gravity in one complete revolution is zero.

-- The total work done by the motor in one complete revolution is only what it takes to pay back the energy robbed by friction and air resistance.

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Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length
Alenkasestr [34]

linear charge density of system of two line charges is given as

\lambda = 5.20 \muC/m

now as we know that electric field due to a line charge at some distance from it is given by

E = \frac{\lambda}{2\pi \epsilon_0 r}

so here we will first find the electric field of first line charge at the position of other line charge

E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}

E = 312000 N/C

now as we know that

F = qE

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

q = \lambda * L

q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C

Now using the above formula

F = qE

F = 0.26 * 10^{-6} * 312000

F = 0.0811 N

so force on the part of wire is F = 0.0811 N

8 0
3 years ago
3. You drop an egg out of your 10 m 2nd story window. If it took 1.43 sec, calculate the
zhannawk [14.2K]

Answer:

15 is the answer

Explanation:

i multiplied 1.5 by 10 to get 15

8 0
3 years ago
F a forklift raises a 76-kg load a distance of 2.5 m, about how much work has it done?
sleet_krkn [62]

W= FxD. Since the weight is not put into force you’re going to convert it by multiplying it by 9.8 (gravity). 76kg x 9.8 = 7448. Then multiply that by the distance (2.5). Your answer is 1862.

6 0
4 years ago
What is the total translational kinetic energy in a test chamber filled with nitrogen (N2) at 2.02×105 Pa and 20.7°C? The dimens
Mumz [18]

Answer:

K. E = 6.0796 × 10^ -21 Joule

Explanation: see attachment

3 0
4 years ago
what is formed when two or more substances are so evenly mixed that you can't see the different parts
Andre45 [30]
A homogenous mixture
5 0
4 years ago
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