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Vlada [557]
3 years ago
6

A person is riding on a Ferris wheel of radius R. He starts at the lowest point of the wheel. When the wheel makes one complete

revolution, is the net work done by the gravitational force positive, zero or negative? Do you need to know how the speed of the person changed before you can answer the question?
Physics
1 answer:
Wittaler [7]3 years ago
4 0

Answering the two questions in reverse order:

-- No. I don't need to know how the speed of the person changed before I can answer the question.  I can answer it now.

-- The NET work done by the gravitational force is<em> zero</em>.

-- As the person and his girl-friend go up the first half of the wheel, the motor does positive work and gravity does negative work.

-- After they pass the peak at the top and come down the second half of the wheel, the motor does negative work and gravity does positive work, even though the couple may be interested in other things during that time.

-- The total work done by gravity in one complete revolution is zero.

-- The total work done by the motor in one complete revolution is only what it takes to pay back the energy robbed by friction and air resistance.

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Suppose your network is connected to another network via a router. Which OSI model layer provides the information necessary to d
RUDIKE [14]

Answer: it is called the "NETWORK LAYER"

Explanation: OSI model means Open System Interconnection model. It have different model layers.

The network layer is the OSI model layer that helps in forwarding packets from network to network, using a network router. It's main function is to connect different network together. It also determine the best virtual circuits(paths) for the data to travel.

Because the question specify that the network is connected to a network router, that means the OSI model layer is network layer.

8 0
3 years ago
A copper rod has a length of 1.3 m and a cross-sectional area of 3.6 10-4 m2. One end of the rod is in contact with boiling wate
sdas [7]

To solve the problem it is necessary to apply the concepts related to heat flow,

The heat flux can be defined as

\frac{dQ}{dt} = H = \frac{kA\Delta T}{d}

Where,

k = Thermal conductivity

A = Area of cross-sectional area

d = Length of the rod

\Delta T= Temperature difference between the ends of the rod

k =388 W/m.\°C Thermal conductivity of copper rod

A = 3.6 *10^{-4} m Area of cross section of rod

\Delta T=100-0=100\°C Temperature difference  

d=1.3m length of rod

Replacing then,

H = \frac{kA\Delta T}{d}

H = \frac{(388)(3.6 *10^{-4})(100)}{1.3}

H=10.7446J

From the definition of heat flow we know that this is also equivalent

H = \dot{m}*L

Where,

\dot{m} = Mass per second

L = 334J/g Latent heat of fusion of ice

Re-arrange to find \dot{m},

H = \dot{m}*L

\dot{m}=\frac{L}{H}

\dot{m}=\frac{334}{10.7446}

\dot{m} = 31.08g/s

\dot{m}= 0.032g/s

Therefore the mass of ice per second that melts is 0.032g

7 0
3 years ago
I need this to be correct and explane why its that answer.
Tanya [424]

Answer:

option A is your answer hope it will help you

4 0
2 years ago
A police officer in hot pursuit of a criminal drives her car through an unbanked circular (horizontal) turn of radius 300 m at a
Mamont248 [21]

Answer:

The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>

Explanation:

Given:

Mass of the driver is, m=55\ kg

Radius of circular turn is, R=300\ m

Linear speed of the car is, v=22.2\ m/s

Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.

The forces are:

1. Weight = mg=55\times 9.8=539\ N

2. Centripetal force, 'F', which is given as:

F=\frac{mv^2}{R}\\F=\frac{55\times (22.2)^2}{300}\\\\F=\frac{55\times 492.84}{300}\\\\F=\frac{27106.2}{300}=90.354\ N

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,

\tan \theta=\frac{90.354}{539}\\\tan \theta=0.1676\\\theta=\tan^{-1}(0.1676)=9.52\approx 10°

Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.

3 0
2 years ago
You happen to know that the coefficient of static friction between your patio table and the ground is 0.42. You decide you want
Deffense [45]

Answer:

If the force applied is larger than 185.2 N, yes.

Explanation:

In order to move the table, the pushing force must be larger than the frictional force. The frictional force is given by:

F_f = \mu mg

where

\mu=0.42 is the coefficient of static friction

m=45 kg is the mass of the table

g=9.8 m/s^2 is the gravitational acceleration

Substituting,

F_f=(0.42)(45 kg)(9.8 m/s^2)=185.2 N

So, we are able to move the table if we push with a force larger than 185.2 N.

4 0
3 years ago
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