linear charge density of system of two line charges is given as

now as we know that electric field due to a line charge at some distance from it is given by

so here we will first find the electric field of first line charge at the position of other line charge


now as we know that

here q = charge on the line charge system at which force is required
E = electric field on that system of charge where force is required
now we can find the charge by


Now using the above formula



so force on the part of wire is F = 0.0811 N
Answer:
15 is the answer
Explanation:
i multiplied 1.5 by 10 to get 15
W= FxD. Since the weight is not put into force you’re going to convert it by multiplying it by 9.8 (gravity). 76kg x 9.8 = 7448. Then multiply that by the distance (2.5). Your answer is 1862.
Answer:
K. E = 6.0796 × 10^ -21 Joule
Explanation: see attachment